MHB Discover All Possible 8-Digit Multiples of 2013 with $A = \overline{20abcd13}$

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The discussion focuses on finding all possible 8-digit numbers of the form $A = \overline{20abcd13}$ that are multiples of 2013. Participants explore the constraints imposed by the structure of $A$ and the divisibility rule for 2013. The calculations involve determining the range of values for the digits $a$, $b$, $c$, and $d$ that satisfy the multiple condition. The conversation emphasizes the importance of modular arithmetic in narrowing down the valid combinations. Ultimately, the goal is to identify all valid 8-digit multiples of 2013 fitting the specified format.
Albert1
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$A=\overline{20abcd13}$ is an 8-digit number ,

also $A$ is a multiple of 2013,please find all possible value of $A$
 
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we know 20132013 multiple of 2013
as 20abcd13 = 20132013 + 201300 * x
so the soultions are 20132013 + 201300 * x as last 2 digits are 13
x= 0 gives 20132013
x =1 gives 20333313
x=2 gives 20534613
x=3 gives 20735913
x=4 gives 20937213
x >=5 gives value outside range
 
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I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

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