Discover the Distance Between Banjul and Accra: 2000 km & a Bearing of 295°"

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Discussion Overview

The discussion revolves around calculating the distance from Accra to Banjul, given a distance of approximately 2000 km and a bearing of 295°. Participants explore methods to determine how far north of Accra Banjul is, involving trigonometric functions and geometric representations.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant asks for guidance on how to find the distance north of Accra to Banjul.
  • Another suggests drawing a right triangle and using trigonometric functions to find the unknown side.
  • A bearing of 295° is noted to correspond to W 15° N, which is used to set up the problem geometrically.
  • There is a correction regarding the interpretation of the bearing, with a participant clarifying that 295° translates to W 25° N.
  • One participant claims to have found the answer, stating it is 845 km, and another confirms this is correct, rounded to the nearest km.
  • A formula is provided for calculating the distance using the cosine of the bearing.

Areas of Agreement / Disagreement

Participants generally agree on the method to calculate the distance and the final answer of 845 km, although there was a correction regarding the bearing interpretation.

Contextual Notes

The discussion includes some assumptions about the geometric representation and the application of trigonometric functions, which may depend on the definitions of bearings and angles used.

Jerome1
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Banjul is approximately 2000 km from Accra. The bearing of Banjul from Accra is 295°. How far north of Accra is Banjul

please give me a clue on how to do this
 
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Can you draw a right triangle, with another known angle and hypotenuse? Then you can use a trig. function to get the unknown side corresponding to the distance you are asked to find.
 
can you help me with that, i'll do the rest myself if you can draw the triangle for me please.
 
A bearing of 295° corresponds to W 15° N...so we may draw the following:

View attachment 2818

$y$ is the distance you want...can you proceed?
 

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MarkFL said:
A bearing of 295° corresponds to W 15° N...so we may draw the following:

View attachment 2818

$y$ is the distance you want...can you proceed?

Surely you mean $\displaystyle \begin{align*} 295^{\circ}\,T = W\,25^{\circ}\,N \end{align*}$...
 
Prove It said:
Surely you mean $\displaystyle \begin{align*} 295^{\circ}\,T = W\,25^{\circ}\,N \end{align*}$...

D'oh! (Doh)

Indeed I do. 295 - 270 = 25...yep.
 
thanks bro...i've gotten the answer
 
it's 845, am i correct?
 
Jerome said:
it's 845, am i correct?

Yes, rounded to the nearest km. :D

In general, you could use:

$$y=2000\cos(\beta)$$

where $\beta$ is the bearing.
 
  • #10
845 is the correct answer.

Tim
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