Discover the Frequency of Fingered Violin Strings Without Measuring Length

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Homework Help Overview

The discussion revolves around determining the frequency of a fingered violin string, given its fundamental frequency of 294 Hz when unfingered. Participants explore how to approach the problem without directly measuring the length of the string at the fingered position.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants question the necessity of knowing the exact length of the string to find the frequency when fingered. Some suggest using a variable (L) to represent the string length instead of needing a specific measurement. Others discuss the relationship between frequency and wavelength, and how changes in length affect frequency.

Discussion Status

The discussion is active, with participants providing hints and exploring different interpretations of the problem. There is no explicit consensus on the approach, but some guidance has been offered regarding the use of variables and the relationship between frequency and length.

Contextual Notes

Participants are working under the constraint of not having the specific length of the string at the fingered position, which raises questions about the assumptions necessary to solve the problem.

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A violin string vibrates at 294 Hz when unfingered. At what frequency will it vibrate if it is fingered one third of the way down from the end?

How do I determine this w/o length of how far 1/3 of violin string is?

Help anyone!
 
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Hint -- you have the information needed to find the length of the string.
 
I thought you needed more information to find the length. But in any case...

needhelp83 said:
How do I determine this w/o length of how far 1/3 of violin string is?
Why do you think you need to know? Have you considered just calling the length L, and seeing if you can do the problem?
 
are you familiar with the relation between wavelength and frequency?

also: what is the speed of sound in air?
 
Does it matter what the actual length is? Surely as Hurkyl points out, length can be simply L. It's merely the freq and the change in length that's important.
 
f1= 294 Hz (fundamental frequency)
f2= 2f1=(2)( 294 Hz)= 588 Hz
f3= 3f1=(3)( 294 Hz)= 882 Hz
f4= 4f1=(3)( 294 Hz)= 1176 Hz

The 294 Hz would be the fundamental frequency and 1/3 the way down would be 1176. Would this be the correct way to solve?
 

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