Distance - Finding Equilibrium Point for Net Force

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Homework Help Overview

The problem involves determining the distance from the Earth at which an astronaut would experience no net force due to the gravitational pulls of both the Earth and the Moon when they are aligned. The subject area includes gravitational forces and equilibrium in a two-body system.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts a force analysis but expresses uncertainty about the setup. They consider the condition where the gravitational pulls from the Earth and Moon on the astronaut are equal. Other participants question the unknown distance from the Moon to the astronaut and suggest drawing a diagram to clarify the situation.

Discussion Status

The discussion has progressed with some participants providing hints and guidance. One participant successfully identifies a relationship between the distances involved, leading to a clearer path for solving the problem. However, multiple interpretations and approaches are still being explored.

Contextual Notes

Participants note the lack of information regarding the distance from the Moon to the astronaut, which is crucial for solving the problem. There are also references to specific values for the masses of the Earth and Moon, as well as the gravitational constant.

ecthelion4
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Homework Statement



At what distance from the Earth should an astronaut be placed so that he will feel no net force when the Earth and the Moon and he are aligned?

Homework Equations



Fnet=ma
F=(Gm1m2)/d^2

The Attempt at a Solution



I assume I'm going to do a force annalysis, I'm just not sure how to. Also I thought that maybe if the pull from the moon to the astronaut and the pull from the Earth to the astronaut were equal, he should feel no force.
 
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Thats exactly right. Youve got the equations, youve figured it out. Just do the math.
 
I got a problem though. I have no way of knowing the distance from the moon to the astronaut. If the forces are equal, and I need to know the distance from the astronaut to the earth, then the resulting equation cleared for d1 (d1 being the distance from the Earth to the astronaut), ends up as this:

d1^2=(m2*d2^2)/m3

m2 being the mass of the earth, m3 being the mass of the moon and d2 being the distance from the astronaut to the moon. I got that equation clearing this in terms of d1 :

(G*m1*m2)/d1^2=(G*m1*m3)/d2^2

G is the gravitational constant and m1 is the mass of the astronaut.
 
Last edited:
ecthelion4 said:
I have no way of knowing the distance from the moon to the astronaut.
Hint: What's d1 + d2 equal?
 
Chaos, he has the right equations however there's some things that aren't apparent.

Draw a picture first of all of this happening and some things will become apparent.
 
I did it :biggrin: All I needed was what Doc Al said. d2 would be the distance from the Earth to the moon minus d1, and since I had only one variable left, the rest was algebra. Thanks!
 
I'd solve it like this instead ->

( G*Mm*m ) / Rm^2 = (G*Me*m) / Re^2

Rm = Re * sqrt( Mm / Me );

Alpha = Rm + Re = 3.84x10^8 m.

Alpha = Re * sqrt(Mm / Me) + Re; Algebraically pull out the Re.

Alpha = Re * [ sqrt(Mm / Me) + 1 ]

Re = Alpha / [ sqrt(Mm / Me) + 1 ]

Mm = 7.35x10^22 Kg; Me = 5.98x10^24 Kg
Re = 3.84x10^8 / [ sqrt(7.35x10^22 / 5.98x10^24) + 1 ]

Re = 3.46x10^8 m
 
Last edited:

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