Distance-time Graph and Velocity-time Graphs

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To draw a velocity-time graph from a distance-time graph, first identify the slope of the distance-time graph at various points, as this slope represents velocity. Set up the velocity-time graph with the same time scale as the distance-time graph for consistency. For each time point, determine the slope of the distance-time graph, which can be done by visualizing a tangent line at that point. Plot these slope values on the velocity-time graph to represent the velocity at each corresponding time. This method allows for a clear transition from distance to velocity representation.
Alain12345
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Can someone please explain to me how to draw a velocity-time graph from a distance-time graph? Are there any general rules about drawing a VT graph from DT graph?

Thanks a lot.
 
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From a DT graph, you can obtain the velocity at different times. With that information you can draw your VT graph.
 
Are you familiar with the mathematical relationships between position, velocity and acceleration?
 
Yes I am, but I'm having trouble drawing th graphs.
 
Alain12345 said:
Yes I am, but I'm having trouble drawing th graphs.
Well then, if the velocity is constant, what does the position do with respect to time?
 
Velocity is the slope on the distance vs. time graph.

Beneath your distance vs time graph, setup the axes for the velocity vs time... choose the same scale on the time axis for both position and velocity... and line them up.

Now, for each time t, visit the point [event] on the position graph and imagine zooming in. Assuming a smooth enough motion, the graph near that point looks like a line [in your viewport]. Determine the slope of that line and plot, for that time t, the value on the velocity graph. [If you are just doing a sketch, just approximate that slope... is the slope positive, negative, or zero? After advancing to a later time, does that slope increase, decrease or stay the same? It may help to "ride the position graph" with your left hand.]

Try that out.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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