- #1

JC2000

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- 15

## Homework Statement

:[/B]The following expression stands for the two angular bisectors for two lines :

[tex]\frac{a_{1}x+b_{1}y+c_{1}}{\sqrt{a_{1}^{2}+b_{1}^{2}}}=\pm \frac{a_{2}x+b_{2}y+c_{2}}{\sqrt{a_{2}^{2}+b_{2}^{2}}}\qquad[/tex]

## Homework Equations

The equations for the two lines are :

##a_1x + b_1y + c_1 = 0~##and ##a_2x + b_2y + c_2 = 0~##

## The Attempt at a Solution

One way is to find the slope from the equation for the respective bisectors and then use the slope of one of the given lines and then apply the formula for angle between two lines to check if the bisector is acute or not. I was wondering if there was a more direct way to do this.

**Since the two lines can be bisected in two ways, is there a formula to distinguish between the bisector that bisects the external angle and the bisector that bisects the internal or acute angle between the two lines?**

My questions :

(A)

My questions :

(A)

My book says that if [tex] a_1 * a_2 + b_1 * b_2 > 0[/tex] then this refers to the external bisector.

I am stumped by this because :

**(B)**How is this expression arrived at?

**(C)**Since [tex]a_1, a_2, b_1, b_2[/tex] all refer to the original equations of the two lines and not the bisectors, which bisector do this expression refer to?

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