Distinguishing between two quantum states

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SUMMARY

The discussion focuses on distinguishing between two quantum states, specifically |0> and a superposition state cos(φ)|0> + sin(φ)|1>, using unitary operations and measurements. It highlights that if |0> and |1> are eigenstates of the Hamiltonian with different energies (E_0 and E_1), measuring the average energy can provide insights into the chosen state. The discussion also emphasizes the role of non-commuting operators with the Hamiltonian in observing oscillations in physical magnitudes when in a superposition state.

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i'm given either |0> or cos[tex]\phi[/tex]|0> + sin[tex]\phi[/tex]|1> by a fair coin toss.
and I don't know which state I'm given.

i need guess which state was chosen.

i think the method is to do a unitary operation on the states, and do the measurement,
but I'm not sure how to construct a unitary, and I'm still not clear what this creating unitary and doing the measure is doing.

need help please.

thank you
 
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It depends on what measurement you can carry out.

If |0> and |1> are eigenstates of the Hamiltonian with energies [tex]E_0[/tex] and [tex]E_1[/tex] ([tex]E_0 \neq E_1[/tex]) and you can measure the average energy of the system, then you will get

[tex] <\!0|\hat{H}|0\!> = E_0[/tex]

[tex] (\cos\phi<\!0| + \sin\phi<\!1|)\hat{H}(\cos\phi|0\!> + \sin\phi|1\!>) =<br /> E_0 \cos^2\!\phi \,+ E_1 \sin^2\!\phi[/tex]

For any operator [tex]\hat{A}[/tex] which does not commute with the Hamiltonian:

[tex] <\!0|\hat{A}|0\!> = A_0 = \text{const}[/tex]

[tex] (\cos\phi<\!0|e^{i\omega_0 t} + \sin\phi<\!1|e^{i\omega_1 t})<br /> \hat{A}<br /> (\cos\phi|0\!>e^{-i\omega_0 t} + \sin\phi|1\!>e^{-i\omega_1 t}) = A_1(t)[/tex]

i.e. you can observe oscillations of some physical magnitudes when the system is in the superposition state.
 

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