Dividing Line Segments into Four Equal Parts using Midpoint Formula

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Discussion Overview

The discussion revolves around the mathematical problem of dividing line segments into four equal parts using the Midpoint Formula. Participants explore the application of this formula to specific points and seek hints for solving related exercises.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Exploratory

Main Points Raised

  • One participant outlines the process of using the Midpoint Formula three times to find the three points that divide a line segment into four equal parts.
  • Another participant provides an example with specific coordinates and describes the calculation of midpoints for intervals formed by the endpoints and the calculated midpoints.
  • There is a discussion about the length of the line segments involved, with one participant initially miswriting the length of a segment and later correcting it, leading to a clarification of the distance formula.
  • Participants express interest in the implications of the distance formula in relation to the lengths of the segments being discussed.

Areas of Agreement / Disagreement

Participants generally agree on the method of using the Midpoint Formula, but there are some discrepancies regarding the specific calculations of lengths and the initial examples used. The discussion remains somewhat unresolved as participants clarify their points without reaching a consensus on the exact details.

Contextual Notes

Some assumptions about the definitions of points and lengths are not explicitly stated, and there are unresolved details regarding the calculations of distances between points.

nycmathdad
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55. Use the Midpoint Formula three times to find the three points that divide the line segment joining (x_1, y_1) and (x_2, y_2) into four equal parts.

56. Use the result of Exercise 55 to find the points that divide each line segment joining the given points into four equal parts.

(a) (x_1, y_1) = (1, −2)

(x_2, y_2) = (4, −1)

(b) (x_1, y_1) = (−2, −3)

(x_2, y_2) = (0, 0)

Looking for hints to solve 55 and 56.
 
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nycmathdad said:
55. Use the Midpoint Formula three times to find the three points that divide the line segment joining (x_1, y_1) and (x_2, y_2) into four equal parts.

56. Use the result of Exercise 55 to find the points that divide each line segment joining the given points into four equal parts.

(a) (x_1, y_1) = (1, −2)

(x_2, y_2) = (4, −1)

(b) (x_1, y_1) = (−2, −3)

(x_2, y_2) = (0, 0)

Looking for hints to solve 55 and 56.
Interpolate Country Boy's explanation at
https://mathhelpboards.com/threads/midpoint-formula.28521/#post-124867
 
The three points needed are the midpoint, p, of the given interval and the midpoint of the two intervals having one of the original endpoint and p as endpoints and the other original endpoint and p as endpoints.

For example, if an interval has endpoints (0, 0) and (2, 2), of length $\sqrt{2}$, has midpoint (1, 1). The midpoint of the interval from (0, 0) to (1, 1) is (1/2, 1/2) and the mid point of (1, 1) to (2, 2) is (3/2, 3/2). The four intervals from (0, 0) to (1/2, 1/2), from (1/2, 1/2) to (1, 1), from (1, 1) To (3/2, 3/2), and from (3/2, 3/2) all have length $\frac{\sqrt{2}}{2}$.
 
Country Boy said:
The three points needed are the midpoint, p, of the given interval and the midpoint of the two intervals having one of the original endpoint and p as endpoints and the other original endpoint and p as endpoints.

For example, if an interval has endpoints (0, 0) and (2, 2), of length $\sqrt{2}$, has midpoint (1, 1). The midpoint of the interval from (0, 0) to (1, 1) is (1/2, 1/2) and the mid point of (1, 1) to (2, 2) is (3/2, 3/2). The four intervals from (0, 0) to (1/2, 1/2), from (1/2, 1/2) to (1, 1), from (1, 1) To (3/2, 3/2), and from (3/2, 3/2) all have length $\frac{\sqrt{2}}{2}$.

Interesting. By the length sqrt{2}, you mean the distance between two given points. This is found using the distance formula for points. True?
 
Yes, although I miswrote. I was first thinking of (0, 0) to (1, 1) which does have length $\sqrt{2}$. But then I changed to (0, 0) to (2, 2) which is twice as long: $\sqrt{(2- 0)^2+ (2- 0)^2}= \sqrt{4+ 4}= \sqrt{4(2)}= 2\sqrt{2}$.
 
Country Boy said:
Yes, although I miswrote. I was first thinking of (0, 0) to (1, 1) which does have length $\sqrt{2}$. But then I changed to (0, 0) to (2, 2) which is twice as long: $\sqrt{(2- 0)^2+ (2- 0)^2}= \sqrt{4+ 4}= \sqrt{4(2)}= 2\sqrt{2}$.

Ok. Interesting.
 

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