MHB Divisors of $2^2.3^3.5^3.7^5$ & $7!$ in the Form of $4n+1$, $3t+1$

[juantheron]

(1) The number of divisers of the form $2^2.3^3.5^3.7^5$ which are is in the form of $4n+1$ where $n\in\mathbb{N}$

(2) Calculate Total no. of positive Divisers of $7!$ which are is in the form of $3t+1\;,$ where $t\in \mathbb{N}$

 

[I like Serena]

(1) The number of divisers of the form $2^2.3^3.5^3.7^5$ which are is in the form of $4n+1$ where $n\in\mathbb{N}$

(2) Calculate Total no. of positive Divisers of $7!$ which are is in the form of $3t+1\;,$ where $t\in \mathbb{N}$

Hi jacks! :)

Where are you stuck?
Did you try anything?