Do Factoring and Simplification Affect the Domain of a Function?

  • Context: Undergrad 
  • Thread starter Thread starter Ryuzaki
  • Start date Start date
Click For Summary
SUMMARY

The discussion clarifies the relationship between factoring, simplification, and the domain of functions. Specifically, the function f(x) = (x^2)/x has a domain of ℝ-{0}, while the function g(x) = x has a domain of ℝ. Although f and g are equivalent for all nonzero x, they are not the same function due to the undefined nature of f at x=0. The conclusion emphasizes the importance of determining the domain based on the original function rather than solely relying on simplification.

PREREQUISITES
  • Understanding of function domains
  • Knowledge of algebraic simplification techniques
  • Familiarity with the concept of undefined values in functions
  • Basic calculus principles related to limits and continuity
NEXT STEPS
  • Study the concept of domain restrictions in rational functions
  • Learn about the implications of simplification on function behavior
  • Explore the differences between removable and non-removable discontinuities
  • Investigate the role of limits in determining function continuity
USEFUL FOR

Mathematics students, educators, and anyone interested in understanding the nuances of function domains and the effects of algebraic manipulation on them.

Ryuzaki
Messages
46
Reaction score
0
Suppose I have a function f defined on x, f(x) = (x^2)/x and another function g defined on x, g(x) = x. Are both these functions the same?

I mean, when you try to determine the Domain of a function, do you simplify it as much as possible, and then find the Domain? Or find the Domain on the face of the function?

In this case, what I think is that f has Domain-->ℝ-{0}, while g has Domain--> ℝ. Is this correct?
 
Physics news on Phys.org
No, they are not the same. Indeed, f is not defined in 0, while g is.

However, f(x) and g(x) are the same for all nonzero x.
 
But of course, you can simplify without altering domains.

[tex]f(x) = g(x), ~ \forall x, ~ \mbox{if} ~ f(x)=1 ~ \mbox{and} ~ g(x) = \frac{x^2 +1}{x^2 +1}[/tex]

Bottom line, find the domain and see if it changes by any possible factoring/simplification.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K