Does a Quadratic Quantum Well with Given Parameters Have Three Bound States?

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1. Consider a quantum well described by the potential [tex]v(x)=kx^{2}[/tex] for [tex]\left|x\right|<a[/tex] and [tex]v(x)=ka^{2}[/tex] for [tex]\left|x\right|>a[/tex]. Given
[tex]a^{2}\sqrt{km}/\hbar<br /> =2[/tex], show that the well has 3 bound states and calculate the ratios between the energies and [tex]ka^{2}[/tex].
You may use the standard integral [tex]\intop(1-y^{2})^{1/2}dy=\frac{\pi}{2}[/tex]


I am not sure how to begin the question, really stuck... Would love some help to get me started.
 
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Have you studied the solution for a harmonic oscillator yet?
 
No but I know I'm not meant to do it like that...
 

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