Does a Quadratic Quantum Well with Given Parameters Have Three Bound States?

AI Thread Summary
A quantum well defined by the potential v(x)=kx² for |x|<a and v(x)=ka² for |x|>a is analyzed for bound states. The condition a²√(km)/ħ=2 is crucial for determining the number of bound states. Participants discuss the relationship between the well's parameters and the energies of the bound states, emphasizing the need for a systematic approach to the problem. The integral provided is a key tool for calculating the ratios of the energies to ka². The discussion highlights the importance of understanding quantum mechanics concepts, particularly in relation to harmonic oscillators, to solve the problem effectively.
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1. Consider a quantum well described by the potential v(x)=kx^{2}<br /> for \left|x\right|&lt;a<br /> and v(x)=ka^{2} for \left|x\right|&gt;a. Given
a^{2}\sqrt{km}/\hbar<br /> =2, show that the well has 3 bound states and calculate the ratios between the energies and ka^{2}.
You may use the standard integral \intop(1-y^{2})^{1/2}dy=\frac{\pi}{2}<br />


I am not sure how to begin the question, really stuck... Would love some help to get me started.
 
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