Does a Quadratic Quantum Well with Given Parameters Have Three Bound States?

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SUMMARY

The discussion focuses on analyzing a quadratic quantum well defined by the potential function v(x) = kx² for |x| < a and v(x) = ka² for |x| > a. It is established that under the condition a²√(km)/ħ = 2, the well indeed supports three bound states. Participants are encouraged to utilize the integral ∫(1 - y²)^(1/2) dy = π/2 to assist in calculating the energy ratios relative to ka².

PREREQUISITES
  • Understanding of quantum mechanics, particularly potential wells
  • Familiarity with the harmonic oscillator model in quantum physics
  • Knowledge of integral calculus, specifically the evaluation of definite integrals
  • Basic grasp of bound states in quantum systems
NEXT STEPS
  • Study the properties of harmonic oscillators in quantum mechanics
  • Learn about the mathematical techniques for solving quantum well problems
  • Research the implications of bound states in quantum systems
  • Explore the application of integrals in quantum mechanics, particularly in potential energy calculations
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Students and researchers in quantum mechanics, physicists focusing on quantum systems, and anyone interested in the mathematical foundations of quantum wells and bound states.

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1. Consider a quantum well described by the potential v(x)=kx^{2}<br /> for \left|x\right|&lt;a<br /> and v(x)=ka^{2} for \left|x\right|&gt;a. Given
a^{2}\sqrt{km}/\hbar<br /> =2, show that the well has 3 bound states and calculate the ratios between the energies and ka^{2}.
You may use the standard integral \intop(1-y^{2})^{1/2}dy=\frac{\pi}{2}<br />


I am not sure how to begin the question, really stuck... Would love some help to get me started.
 
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Have you studied the solution for a harmonic oscillator yet?
 
No but I know I'm not meant to do it like that...
 

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