Does anyone know the answer (s) to this?

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SUMMARY

The discussion focuses on optimizing the power required for an electric car's motion, modeled by the equation P = Av² + (B/v), where A and B are positive constants. The optimal speed vP that minimizes power is derived as v = ∛(B/(2A)). The participants also explore the implications of varying A and B on the graph of power, emphasizing the importance of understanding concavity to determine whether the result is a minimum or maximum. The analysis provides a mathematical foundation for evaluating electric vehicle efficiency.

PREREQUISITES
  • Understanding of calculus, specifically derivatives and optimization techniques.
  • Familiarity with algebraic manipulation and solving equations.
  • Basic knowledge of electric vehicle dynamics and power consumption models.
  • Experience with graphing functions to analyze concavity and behavior of equations.
NEXT STEPS
  • Study the implications of varying constants A and B on the power equation.
  • Learn about the application of calculus in optimizing performance metrics in electric vehicles.
  • Explore energy storage and efficiency calculations for electric vehicles.
  • Investigate the impact of drag coefficients on electric vehicle performance.
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Mathematicians, engineers, electric vehicle designers, and anyone interested in optimizing electric vehicle performance through mathematical modeling.

Jimmy Perdon
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A simplified model of the power P required to sustain the motion of an electric car at speed v experiencing nonzero drag can be modeled by the equation:

P = Av^2 + (B/v)
(where A and B are positive constants.)

(a) What speed vP minimizes power?
(b) What power does the speed in (a) require?
(c) Suppose that an electric car has a usable store E of energy. How far dP can the electric car travel at the
speed found in (b)?
 
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Here's the derivative for the function of power, $$ P=Av^2+\frac{B}{v} (\text{Where }A\text{ and }B\text{ are positive constants)} $$ that they give in the introduction to the problem:

$$ P'(v)=2Av-\frac{B}{v^2} $$

To answer $$ \text{(a) What speed }vP\text{ minimizes power?} $$ we set this expression equal to $$ 0 $$ and solve for $$ v $$:

$$
\begin{align*}
2Av-\frac{B}{v^2}&=0 \\
2Av&=\frac{B}{v^2} \\
2Av\cdot\frac{v^2}{B}&=\frac{B}{v^2}\cdot\frac{v^2}{B} \\
\frac{2Av\cdot v^2}{B}&=1 \\
\frac{2Av^3}{B}\cdot\frac{B}{2A}&=1\cdot\frac{B}{2A} \\
v^3&=\frac{B}{2A} \\
v=\sqrt[3]{\frac{B}{2A}} \\
\end{align*}
$$

Now we need to determine if this result is a minimum or a maximum and we do this by examining the concavity of the graph of $$ P $$

I'll let you take a look at the graph and experiment with the different values for $$ A $$ and $$ B $$. As a suggestion, take a look at the graph when $$ A $$ and $$ B $$ are different signs.[DESMOS]{"version":7,"graph":{"viewport":{"xmin":-10,"ymin":-7.65696784073507,"xmax":10,"ymax":7.65696784073507}},"randomSeed":"86f5ca9aa79de8cb0e8d39ee14441c5a","expressions":{"list":[{"type":"expression","id":"1","color":"#c74440","latex":"P=2Av^{2}+\\frac{B}{v}"},{"type":"expression","id":"3","color":"#388c46","latex":"B=-1","hidden":true},{"type":"expression","id":"2","color":"#2d70b3","latex":"A=-1","hidden":true}]}}[/DESMOS]
 
Last edited:
https://mathhelpboards.com/threads/does-anyone-know-the-answer-to-this.28654/
 

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