Does Doubling y in an Inverse Proportion Problem Halve the Constant?

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SUMMARY

The discussion centers on the relationship between variables in inverse proportion, specifically examining the equation y ∝ 1/x. When y is doubled to 2y, the proportionality remains consistent, leading to the conclusion that 2y ∝ 1/0.5x. This indicates that doubling y effectively halves the constant in the inverse relationship, confirming that y can be expressed as y = k/x, where k is a constant. Thus, the transformation of y directly influences the constant in the equation.

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Hello

if y [itex]\propto[/itex] 1/x
would 2y [itex]\propto[/itex] 1/0.5x
or 2y [itex]\propto[/itex] 1/2x

thank you for any replies
 
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e44-72 said:
Hello

if y [itex]\propto[/itex] 1/x
would 2y [itex]\propto[/itex] 1/0.5x
or 2y [itex]\propto[/itex] 1/2x

thank you for any replies

if y [itex]\propto[/itex] 1/x then
y [itex]\propto[/itex] 2y [itex]\propto[/itex] 1/0.5x [itex]\propto[/itex] 1/x [itex]\propto[/itex] 1/2x
 
y ∝ 1/x means y = k/x for some constant k. For your question, it means simply change the constant.
 

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