Mathman,
To be frank, I was indeed puzzled by the hint of your post, initially, for quite sometime. Good steam properties calculator like steamtab which is based on IAPWS formulae should never lie, so it became my responsibility to check for a possible solution. This is what comes to my mind.
The specific volume of any gas, at STP, can easily be calculated by Avagadro's law if we know the molecular weight of the gas. Molecular weight of water is 18, as you rightly said, and average molecular weight of air is 29.
So, one lb mole of water vapor occupies 379/18 = 21.05 cu.ft at STP. So the density is about 1/21.05 = 0.0475lb/cu.ft. One lb mole of air occupies 379/29 = 13.07 cu.ft at STP. So the density is about 1/13.07 = 0.0765lb/cu.ft. So what you said should be right.
But the key word here is STP(14.696psia and 60F - a general standard, though there are many variations to the definition of STP). The saturation pressure of water vapor, at 60F, is 0.256398psia. So, you have to expand the water vapor from 14.696psia to 0.256398psia(isothermally) and the ratio is about 57.31. So the density should be 0.0475/57.31 = 0.0008288lb/cu.ft. This is close to the value I specified above and I think my procedure is fair if not accurate.
Thanks for pointing out.
Regards,