Does intensity determine the occurrence of the photoelectric effect?

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Discussion Overview

The discussion centers on the relationship between intensity and the occurrence of the photoelectric effect, exploring the conditions under which electrons are emitted from metals when exposed to radiation. Participants examine the role of frequency, energy, and intensity in this phenomenon, considering both theoretical and experimental perspectives.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • Some participants assert that a minimum frequency, known as the threshold frequency, is required for the photoelectric effect to occur, regardless of the intensity of the incident radiation.
  • Others argue that increasing intensity does not contribute to the emission of electrons unless the frequency of the radiation exceeds the threshold frequency.
  • One participant mentions the possibility of multi-photon processes, where multiple photons can contribute to the energy needed to eject an electron, although this is considered less common.
  • There is a discussion about the potential for excess energy from a photon to manifest as kinetic energy of the emitted electron if the photon energy exceeds the threshold.
  • Some participants explore the implications of photon energy on electron transitions between atomic orbits, questioning whether excess energy is entirely rejected or partially absorbed.

Areas of Agreement / Disagreement

Participants generally agree on the necessity of a threshold frequency for the photoelectric effect, but there are competing views regarding the role of intensity and the possibility of multi-photon processes. The discussion remains unresolved on several nuanced points regarding energy absorption and electron behavior.

Contextual Notes

Participants note that the physics of high-intensity radiation and its effects on electron emission can be complex and may not be fully explained by simple models. There are references to multi-photon processes and the limitations of perturbation theory in describing certain phenomena.

Who May Find This Useful

This discussion may be of interest to students and researchers in physics, particularly those studying quantum mechanics, the photoelectric effect, and atomic interactions with electromagnetic radiation.

rohanprabhu
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For the photoelectric effec to take place for a certain metal, there is a minimum frequency that the incident radiation must have, also called the threshold frequency. Let us call it [itex]f_o[/itex].

The electron is emmitted only when a minimum amount of energy is provided to it so that it can repulse the intermolecular forces. This energy, called the 'Work function' is [itex]\phi = f_o[/itex] [where 'h' is the Planck's constant].

Now, if the minimum energy is not provided, the electron is not emitted. No matter how high the intensity of the incident radiation is, the electron won't be emitted unless the radiation has a frequency [itex]f_o[/itex].

But, if it is energy dependent, won't increasing the Intensity increase the energy too? Because,

[tex]I = \frac{dP}{dA}[/tex]

Therefore, if a radiation has a higher intensity, won't it be having a higher value of Power? Which means that the energy supplied per unit time should also be higher. So, for a higher value of Intensity, the energy is more... So why doesn't it show the photoelectric effect unless and until the metal is irradiated with a radiation having a frequency of [itex]f_o[/itex]
 
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the thing is that the energy must come in ONE shot, the electron can't "gather energy".

The energy of a photon is given by its frequency, so you must have a frequency above a certain threshould. The energy of the beam is not the interesting thing, it is the energy of a the individual photons.
 
malawi_glenn said:
the thing is that the energy must come in ONE shot, the electron can't "gather energy".

The energy of a photon is given by its frequency, so you must have a frequency above a certain threshould. The energy of the beam is not the interesting thing, it is the energy of a the individual photons.

ok.. so do you mean to say that an electron is ejected only when it annihilates a photon with the threshold frequency?
 
yes, that is correct. (or higher frequency)
 
It is preumably possible to eject a photon even when the frequency is lower than the "threshold" using a multi-photon process. Two photon processes -where each photon has half the energy- are quite common and are used in spectroscopy. 3 photon processes are rare and higher order processes are as far as I know almost negligle in natural atoms (but can be seen in spectroscopy on e.g. Rydberg atoms). However, there are artifical systems ("quantum well") where tens of photons can "add up" (I think the highest I have ever seen is 13), the probability for such processes increases quite a lot in strongly anharmonic potentials.

Also, the intensity of the radiation DOES matter if it is very high. The reason is simply that the radiation itself can perturb the potential in such a way that the position of the levels are shifted; it is therefore possible to "hit" the resonance simply by driving the system very hard. Due to "ladder" process with virtual levels it is therefore possible to excite systems even when starting far from resonance if the drive amplitude is high enough. Unfortunately, the physics is VERY complicated since these processes can't be treated using perturbation theory and AFAIK there is no "simple" theory.
 
f95toli said:
It is preumably possible to eject a photon even when the frequency is lower than the "threshold" using a multi-photon process. Two photon processes -where each photon has half the energy- are quite common and are used in spectroscopy. 3 photon processes are rare and higher order processes are as far as I know almost negligle in natural atoms (but can be seen in spectroscopy on e.g. Rydberg atoms). However, there are artifical systems ("quantum well") where tens of photons can "add up" (I think the highest I have ever seen is 13), the probability for such processes increases quite a lot in strongly anharmonic potentials.

Also, the intensity of the radiation DOES matter if it is very high. The reason is simply that the radiation itself can perturb the potential in such a way that the position of the levels are shifted; it is therefore possible to "hit" the resonance simply by driving the system very hard. Due to "ladder" process with virtual levels it is therefore possible to excite systems even when starting far from resonance if the drive amplitude is high enough. Unfortunately, the physics is VERY complicated since these processes can't be treated using perturbation theory and AFAIK there is no "simple" theory.

of course more elaborate discussions about the photo electric effect can be made, but this has not so much to do what the OP asked about. He doubted the very basics about the photo eletric effect.
 
malawi_glenn said:
of course more elaborate discussions about the photo electric effect can be made, but this has not so much to do what the OP asked about. He doubted the very basics about the photo eletric effect.

OP??

another question is.. If there is a photon having a frequency higher than [itex]f_o[/itex], but not high enough so that the electron can accept it all [afaik, an electron can accept only a set of particular amounts of energy].. so is this remaining energy rejected? If it is rejected.. does it result in the creation of a new photon of a frequency such that it's energy is the energy difference between the nearest quanta of energy the electron could accept and the one brought in by the incident photon?
 
op = original poster.

if the photons energy is not not enough to remove the electron from the atom, it can do other things, for example excite an atom or heat the solid etc.
 
rohanprabhu said:
OP??

another question is.. If there is a photon having a frequency higher than [itex]f_o[/itex], but not high enough so that the electron can accept it all [afaik, an electron can accept only a set of particular amounts of energy].. so is this remaining energy rejected? If it is rejected.. does it result in the creation of a new photon of a frequency such that it's energy is the energy difference between the nearest quanta of energy the electron could accept and the one brought in by the incident photon?

This is not correct. If the photon energy is larger than the threshold, then the "extra" energy is the kinetic energy of the emitted electron. That is why you see a spectrum of energy for all the photoelectrons emitted.

Zz.
 
  • #10
"If there is a photon having a frequency higher than , but not high enough so that the electron can accept it all " Seems like a condradiction.
 
  • #11
ZapperZ said:
This is not correct. If the photon energy is larger than the threshold, then the "extra" energy is the kinetic energy of the emitted electron. That is why you see a spectrum of energy for all the photoelectrons emitted.

Zz.

forget about the photoelectric effect for a moment. What about the electrons jumping orbits? If it receives photons that can make it jump to the 2nd orbit + a little extra energy, but not enough to make it jump till the 3rd.. does it reject it completely or reject just a part of it?

my teacher told me that it rejects it completely.. though I'm a bit reluctant to agree to that?
 
  • #12
it rejects it when chaning orbits yes.

But imagine the photo electric effect as ionization, the ionization energy of H is 13.6eV, if a photon of E = 20eV enters, the electron will be emitted with 6.4eV kinetic energy. The excitation energy for n=1 to n=2 is 10.4eV, and if the incoming photon has energy 11eV, then it can not excite the electron to that orbit, it does not interact with the atom at all here.
 
  • #13
malawi_glenn said:
it rejects it when chaning orbits yes.

But imagine the photo electric effect as ionization, the ionization energy of H is 13.6eV, if a photon of E = 20eV enters, the electron will be emitted with 6.4eV kinetic energy. The excitation energy for n=1 to n=2 is 10.4eV, and if the incoming photon has energy 11eV, then it can not excite the electron to that orbit, it does not interact with the atom at all here.

thx a lot man.. it helped me understand a lot today :D

/offtopic: are u on this forum all day long?? :P
 
  • #14
I have nothing elso to do man ;) Shall ask some questions here my self, so I want to contribute to this lovley forum by giving answers to something that I understand :P
 
  • #15
malawi_glenn said:
it rejects it when chaning orbits yes.

But imagine the photo electric effect as ionization, the ionization energy of H is 13.6eV, if a photon of E = 20eV enters, the electron will be emitted with 6.4eV kinetic energy. The excitation energy for n=1 to n=2 is 10.4eV, and if the incoming photon has energy 11eV, then it can not excite the electron to that orbit, it does not interact with the atom at all here.

How about a photon with 20.8eV of energy? Any difference?
 
  • #16
dst said:
How about a photon with 20.8eV of energy? Any difference?

energy is still too high right?.. ;)
 

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