Does ln[ln(x)] = ln(x) * ln(x)

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Homework Help Overview

The discussion revolves around the relationship between the expressions ln[ln(x)] and ln(x) * ln(x), exploring whether they are equivalent in the context of logarithmic functions.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants examine the validity of the original statement by considering specific values and discussing the nature of function composition versus multiplication. There are attempts to manipulate the expressions to clarify their differences.

Discussion Status

The discussion is active, with participants providing insights and examples that illustrate the distinctions between the two expressions. Some have offered reasoning that suggests the expressions are not equivalent, while others are exploring further manipulations to clarify the concepts involved.

Contextual Notes

Participants are working within the constraints of understanding logarithmic properties and function behavior, questioning assumptions about the equality of the two expressions.

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Homework Statement


Does ln[ln(x) = ln(x) times ln(x)?


Homework Equations




The Attempt at a Solution

 
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Well, no. Take x=e. ln(e)*ln(e)=1, ln(ln(e))=ln(1)=0.
 
And generally speaking, f(f(x)) is different from f(x)*f(x). It's the difference between function composition (evaluation a function of a function) and function multiplication.
 
Maybe if we manipulated the expression a little it will become clearer that each function is not equal to each other.

ln\left(ln(x)\right)=\left(ln(x)\right)^2

ln(x)=e^{\left(ln(x)\right)^2}

ln(x)=(e^{ln(x)})^{ln(x)}

ln(x)=x^{ln(x)}

Does it look more obvious now as to why these expressions are not equal?
 

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