Does Magnification Affect Both Vertical and Horizontal Dimensions in Lenses?

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Magnification in thin converging lenses affects both vertical and horizontal dimensions equally. The discussion confirms that the geometry is symmetric around the principal axis, meaning that the magnification factor applies uniformly to both height and width. Therefore, when calculating the area of the image, both dimensions are multiplied by the magnification factor, resulting in an inverted image that is larger than the object.

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Mishy
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I was wondering if magnification applies to the vertical and horizontal dimensions, or just the vertical.

The following information is about the question I am dealing with. It won't answer my concern above, but give a sens of what is going on. The question is dealing with a thin lens (converging, if that matters) with the object (face area is given) in front of the lens (+p) and the image behind the lens (+q). Both the object and the image are farther from the lens than the focal point on their respective sides. The image is bigger than the object and is inverted (-M). The question asks for the area of the image. Does that mean the height of the object is multiplied by the magnification as well as the width, or is it just the height that is multiplied by the magnification?

Help would be appreciated, Thanks,
Mishy
 
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Yes.

The geometry is symmetric radially around the principle axis. That means that an arrow set vertically will have the same magnification in length as it would if set horizontally. So again, yes, the magnification for spherical lenses applies identically to width and height.
 

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