Does photon spin imply its polarization

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SUMMARY

The discussion centers on the relationship between photon spin and polarization, specifically addressing whether the magnetic quantum number (m) in the |ℓ m⟩ notation implies polarization states. It is established that the helicity states m=+1 and m=-1 correspond to left and right circularly polarized light, respectively. The state m=0 is not applicable due to the massless nature of photons. Superpositions can describe light with arbitrary but fixed polarization.

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  • Understanding of quantum mechanics, specifically photon properties
  • Familiarity with the concept of spin in quantum particles
  • Knowledge of polarization states in light
  • Basic grasp of quantum state notation, particularly |ℓ m⟩
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a2009
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Hi all,

I know that the photon has spin 1. Does its magnetic number, the m in | \ell m \rangle imply its polarization? For instance if m=1, does that mean it has circular polarization?

Personally I see no connection between the two.

Thanks for any help.
 
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a2009 said:
I know that the photon has spin 1. Does its magnetic number, the m in | \ell m \rangle imply its polarization? For instance if m=1, does that mean it has circular polarization?
The two helicity states m=+1 and m=-1 correspond to left and right circularly polarized light.
Superpositions describe light of arbitrary but fixed polarization.

The state m=0 is forbidden since the photon is massless.
 

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