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- If set S has cardinality 2, does the definition of cardinality imply the existence of an equivalence relation that distinguishes the two elements?
Physics speaks of a set S of N "indistinguishable particles", giving the set S a cardinality but forbidding any equivalence relation that can distinguish between two particles. Is this terminology inconsistent with the mathematical definition of cardinality?
Suppose ##S## is a set with cardinality 2. I want to show that there exists an equivalence ##E## defined on the elements of ##S## using only the definition of cardinality and without assuming such a relation exists. A constructive proof might be as follows:
Since ##S## has cardinality 2 there exists (by definition) a 1-to-1 function mapping the elements of S to those of the set ##\{1,2\}##. Let ##F## be such a mapping. Define an equivalence relation ##E## as follows. Let ##x## be the element in ##S## such that ##F(x) = 1##. Let ##y## be the element in ##S## such that ##F(y) = 2##. By the definition of a function ##x \ne y## (because the same element cannot be mapped to two different numbers.) Define ##E## to be the set of ordered pairs ##\{(x,x),(y,y)\}## Since ##(x,y)## is not an element of ##E## then ##x \ne y## in terms of the equivalence relation ##E##.
That seems straightforward, but the line " By the definition of a function ##x \ne y##" assumes we have some equivalence relation that can be used to determine that ##x \ne y##. Determining that fact is necessary to assure that ##F## is a function. We assume the aforesaid relation exists before we prove ##E## exists. So the mention of a 1-to-1 function in the definition of cardinality assumes the existence of an equivalence relation that we use to determine that two distinguishable elements are not mapped to the same element.
So the physics version of a set of N indistinguishable particles differs from the mathematical concept of a set with cardinality N. (At least that's my opinon.)
Suppose ##S## is a set with cardinality 2. I want to show that there exists an equivalence ##E## defined on the elements of ##S## using only the definition of cardinality and without assuming such a relation exists. A constructive proof might be as follows:
Since ##S## has cardinality 2 there exists (by definition) a 1-to-1 function mapping the elements of S to those of the set ##\{1,2\}##. Let ##F## be such a mapping. Define an equivalence relation ##E## as follows. Let ##x## be the element in ##S## such that ##F(x) = 1##. Let ##y## be the element in ##S## such that ##F(y) = 2##. By the definition of a function ##x \ne y## (because the same element cannot be mapped to two different numbers.) Define ##E## to be the set of ordered pairs ##\{(x,x),(y,y)\}## Since ##(x,y)## is not an element of ##E## then ##x \ne y## in terms of the equivalence relation ##E##.
That seems straightforward, but the line " By the definition of a function ##x \ne y##" assumes we have some equivalence relation that can be used to determine that ##x \ne y##. Determining that fact is necessary to assure that ##F## is a function. We assume the aforesaid relation exists before we prove ##E## exists. So the mention of a 1-to-1 function in the definition of cardinality assumes the existence of an equivalence relation that we use to determine that two distinguishable elements are not mapped to the same element.
So the physics version of a set of N indistinguishable particles differs from the mathematical concept of a set with cardinality N. (At least that's my opinon.)