Does the Force Formula F=m x 10 N/kg Apply to Bodies at Rest or in Motion?

[-Physician]

Homework Statement

Does the force formula $F=m χ 10\frac{N}{kg}$ which means $F=G$, apply for bodies on rest or motion?

Homework Equations

$F=G=m χ 10\frac{N}{kg}$

The Attempt at a Solution

I think it only applies for bodies in rest.

I'm waiting an answer , thanks!

 

[Doc Al]

The formula W = mg gives you the weight of a mass m, regardless of whether it's at rest or in motion.

 

[-Physician]

Weight is G, not W.., anyways I wasn't asking about other formulas, i was asking about my formula $F=mχ10\frac{N}{kg}$

 

[Doc Al]

Weight is G, not W..,

anyways I wasn't asking about other formulas, i was asking about my formula $F=mχ10\frac{N}{kg}$

Where did you get that formula? It sure looks like 'mg' to me, which is weight. Seems like you're using g = 10 m/s^2.

 

[-Physician]

I see you don't know that formula,we use that to find the Pushing force or weight of a body using the mass, which i think that the body is in rest. For example if we have a body with mass 2g, then the weight would be:

$G=mχ10\frac{N}{kg}=\frac{2}{1000}kg χ 10\frac{N}{kg} = \frac{200}{1000}N$(btw. kilogram and kilogram get simplified )

What I wanted to ask is if that formula applies also if the body is in motion

 

[sankalpmittal]

I see you don't know that formula,we use that to find the Pushing force or weight of a body using the mass, which i think that the body is in rest. For example if we have a body with mass 2g, then the weight would be:

$G=mχ10\frac{N}{kg}=\frac{2}{1000}kg χ 10\frac{N}{kg} = \frac{200}{1000}N$(btw. kilogram and kilogram get simplified )

What I wanted to ask is if that formula applies also if the body is in motion

No ! Doc Al got you correct. Your formula is nothing but of weight which is mass times gravity.

F=mg

Newton per kg in your unit gives you gravitational pull..

1 N/kg = 1 m/s²

You are assuming gravity in your formula to be 10 m/s².

So you state that weight = mg = m*10 N/kg
OR
weight = m*10 m/s²
Of course , I guess everyone here know that kg and kg gets simplified..

Your formula is nothing but simple mg where you substituted for g by 10 metre per second squared.

Edit : Of course this formula applies when body is in motion. Doc Al already stated that in previous posts.

 

[-Physician]

So, the gravity is not always $10\frac{N}{kg}$, then why is the Weight/Force formula
$F=mχ10\frac{N}{kg}$

 

[Doc Al]

So, the gravity is not always $10\frac{N}{kg}$, then why is the Weight/Force formula
$F=mχ10\frac{N}{kg}$

That formula applies near the Earth's surface.

 

[-Physician]

Thank you very much, I am new on physics, I am only on the first grade so , I need to learn more :) Thanks@!

 

[-Physician]

Anyways, can the body near the Earth surface be in motion and in rest aswell, or only in rest or only in motion?
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Would...:
$1\frac{N}{kg}=1\frac{m}{s^2}$ because :
$1\frac{N}{kg}=1\frac{m}{s^2}=1\frac{kg\frac{m}{s^2}}{kg}=1\frac{m}{s^2}$kg and kg get simplified $=1\frac{m}{s^2}=1\frac{m}{s^2}$

 

[Doc Al]

Anyways, can the body near the Earth surface be in motion and in rest aswell, or only in rest or only in motion?

I don't know what you mean. A rock (for example) can be in motion or at rest. (Not at the same time within the same reference frame, of course.)

----------------------
Would...:
$1\frac{N}{kg}=1\frac{m}{s^2}$ because :

Sure, those units are equivalent.