Mapping the Unit Disk onto the Complex Plane: A Holomorphic Approach

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Mapping the unit disk holomorphically onto the complex plane is not possible due to the compactness of the unit disk and the non-compactness of the complex plane, which violates the principles of continuous mappings. The Riemann mapping theorem suggests that while mappings exist, they do not apply to the entire complex plane. Liouville's theorem indicates that any entire function that is bounded must be constant, reinforcing the impossibility of such a mapping. However, it is possible to map the open disk onto the upper half-plane using specific functions like the Cayley map. Thus, while direct mapping to the complex plane is not feasible, alternative mappings exist for related domains.
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Is it possible to map the unit disk onto the complex plane C holomorphically?
This is not a homework question. Thank you for your help
 
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Hi there!

This is an interesting question.

The Riemannian mapping thm. actually gives a partial answer to that question - it is possible to find such a mapping, if the domain is not all of C, so the statement is seriously doubted - otherwise Riemann would have stated his thm in a more general way

However, I'll try to sketch a counter proof:

Assume that f: C -> D is holomorphic. It is evident that f is then an entire function. What is more, for all z in C it is true that |f(z)|<=1, i.e. f is bounded, because D is bounded. Now the Liouville's thm implies that f must be constant, implying the statement is incorrect.
(the Liouville's thm is that very nice tool also used for proving the Fundamental Theorem of Algebra in less that 5 lines)


regards,
marin
 
Hi Marin,
I thank you for the response, but I believe you have misread the question. I am looking for a function from D to C. Not the other way around; and, yes, otherwise Liousville's Theorem would make it impossible.

Again: Can you map the unit disk onto C?
Thanks
 
Holomorphic maps are continuous. The unit disk is compact. Continuous maps apply compact set to compact set. The complex plane is not compact. Hence, you can't map continuously (or holomorphically) D onto C.
 
quasar987 said:
Holomorphic maps are continuous. The unit disk is compact. Continuous maps apply compact set to compact set. The complex plane is not compact. Hence, you can't map continuously (or holomorphically) D onto C.

Of course he means the open disk. The disk and the plane are homeomorphic. But not conformally equivalent (as noted, by Liouville's theorem). So what about mapping the open disk onto the complex plane in a many-to-one manner?
 
For some reason I didn't even consider that the OP might mean the open disk!
 
Thank you both of you. I retrospect, I should have made it clearer by saying the open disk.

And, yes, following the suggestion from Edgar
I can use (z-i)^2 to map the upper falf plane onto C and

Cayley map to map the open disk onto the upper half plane. I believe this will do it. Thsnk you again.
 

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