High School Double slit experiment for layman

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SUMMARY

The double slit experiment demonstrates the wave-particle duality of photons, where the probability of a photon landing on a screen is calculated by summing the probability amplitudes of all possible paths. The size and distance of the slits, as well as the introduction of additional slits, such as in a triple slit experiment, do not alter the fundamental principles of the experiment. The photon does not split or travel through multiple slits simultaneously; rather, it follows a single path determined by probability. Understanding these concepts is crucial for grasping the nuances of quantum mechanics.

PREREQUISITES
  • Quantum mechanics fundamentals
  • Probability theory in physics
  • Understanding of wave-particle duality
  • Familiarity with experimental physics apparatus
NEXT STEPS
  • Research the mathematical framework of probability amplitudes in quantum mechanics
  • Explore the implications of the triple slit experiment on quantum theory
  • Study the effects of measurement on quantum systems
  • Investigate practical setups for conducting the double slit experiment
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Students of physics, educators explaining quantum mechanics, and researchers interested in experimental quantum phenomena will benefit from this discussion.

wolram
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In the literature we are told that the double slit experiment works but are given no description of the experiment apparatus
How big are the slits, how far apart are they, or does it matter
Would using 3 slits make a difference, would photon go through A and B, or through B and C, or all 3.
When going through 2 slits is the photon energy halved or doubled., or the same. That would have me scratching my head.
 
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wolram said:
In the literature we are told that the double slit experiment works but are given no description of the experiment apparatus
How big are the slits, how far apart are they, or does it matter
If you google for "practical double-slit experiment" you will find a number of good descriptions.
Would using 3 slits make a difference, would photon go through A and B, or through B and C, or all 3.
When going through 2 slits is the photon energy halved or doubled., or the same. That would have me scratching my head.
Don't be thinking as if the particle is going through both slits (or all three, in a triple-slit experiment). You'll hear it described that way in some popularizations, but that model is very misleading.

What's really going on: We calculate the probability of the particle landing at any point on the screen by summing the probability amplitudes for every possible path between the source and the screen. If there are two slits, there are two possible paths. If there are three slits, there are three possible paths... and so on. But this calculation isn't saying anything about which path the particle follows and it certainly isn't saying that the particle divides into pieces and goes through more than one path.

(If we put a detector in one of the slits, then we know to not count the path through that slit if the detector doesn't trigger, and to count only that path if it does trigger. But the general principle is the same - we're adding the probability amplitudes for all the possible paths between the source and the screen).
 
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Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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