Double-stranded DNA molecule is 22% cytosine

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SUMMARY

A double-stranded DNA molecule with 22% cytosine (C) must contain an equal percentage of guanine (G), resulting in 22% G as well. The remaining percentage of adenine (A) and thymine (T) must be calculated from the total, which is 100%. Since C pairs with G, and A pairs with T, the percentages of A and T must be equal. Therefore, the final composition is 22% C, 22% G, and 28% each for A and T.

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i am stuck on this problem and was hoping someone could help..

If a double-stranded DNA molecule is 22% cytosine, what are the percentages of guanine, adenine, and thymine?

Thanks
 
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Hint: there will be the same amount of one of the other three.
 


thanks, so 26% each
 


Which each, and why 26%?
 


if 22% is is cytosine, i subtract 22 from 100 and get 78, then i divided that by 3 which is 26
so there is 26%, guanine, 26% adenine, and 26% thymine..

Right??
 


No, there must be other base that is present in exactly 22% quantity. Do you know how they pair?
 


T & A pair and C & G pair..
so what are the steps i need to take?
 


wwwaazup said:
so what are the steps i need to take?

Thinking will be enough. If there is 22% of C, how much G do you expect?
 


So the hint u gave me was that there will be the same amount of one of the other three.
Then u said there must be other base that is present in exactly 22% quantity...

im soo lost please help!
 
  • #10


If C pairs with G then there must be equal amounts of each assuming this is good DNA. Draw pictures if it helps.
 
  • #11


wwwaazup said:
So the hint u gave me was that there will be the same amount of one of the other three.
Then u said there must be other base that is present in exactly 22% quantity...

Perhaps my English fails me, but from what I understand you have stated twice exactly the same.
 

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