Drag racing (a symbolic power problem)

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SUMMARY

The discussion focuses on calculating the elapsed time for a dragster race under constant instantaneous power conditions. The key equation derived is t = (m*a*d)/P, which simplifies to t = ((3d/2)^(2/3))((m/2P)^(1/3)) as stated in the textbook. The participant emphasizes the need for integration to derive the cube root relationship and suggests that understanding the derivation of the power equation P = Fv is crucial for solving the problem. The discussion highlights the importance of conceptual clarity in applying physics principles to real-world scenarios.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Familiarity with the power equation (P = Fv)
  • Basic knowledge of integration techniques in calculus
  • Concept of work and energy in physics
NEXT STEPS
  • Study the derivation of the power equation P = Fv in detail
  • Learn about integration techniques relevant to physics problems
  • Explore the relationship between work, energy, and power in mechanical systems
  • Practice solving problems involving constant power and variable acceleration
USEFUL FOR

Physics students, engineering students, and anyone interested in understanding the dynamics of drag racing and power mechanics in motion.

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Homework Statement



A dragster of mass m races another a distance d from a dead stop. Assume a constant instaneous power P for the entire race (provided by engine) and the dragster is like a particle. Find the elapsed time for the race.


Homework Equations



Well, P = Fv is needed for this I know, and F = ma and v = d/t

so P = (m*a*d)/t

and Pt = m*a*d

so t = (m*a*d)/P

The Attempt at a Solution



Ok, I thought that the final equation was enough, but evidently there is some manipulating of variables that I am oblivious to, because hte back of the book says t = ((3d/2)^(2/3))((m/2P)^(1/3)).

I have no idea where a cube or cube root would come into play in determining the time. I have a feeling there is some integration involved, but how would a work integral give me what the book says?

So you now know I am not looking for an answer, but a method. (Judging by the fact that these conditions have been mandated for the first time I have seen them, I'm guessing people were just trying to get easy answers. I just want to learn the problem solving technique from the pros.)
 
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Integration will be required. Also, you need to go one step back from P = Fv to see where that relationship comes from and decide if it is valid in your problem.
 
Another approach would be to remember that power is change in energy per unit time. So the change in energy per time is constant in this problem.
 

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