Dx as change in distance vs dx as infinitesimal x?

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jaredvert
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dx as change in distance vs dx as infinitesimal x?

Why are they the same notation?Sent from my iPhone using Physics Forums
 
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Because they're the same thing. What meaning exactly would [itex]dx[/itex] have otherwise?

If at time [itex]t[/itex] you have some position [itex]x(t)[/itex] then Newton's Law tells you how a small change in position is related to the velocity of the particle - namely [itex]x + dx = x + v(t)dt[/itex], where [itex]v(t)[/itex] satisfies the equation [itex]m\frac{dv}{dt} = F[/itex].
 
An actual change in distance is often denoted by δx or Δx, to distinguish it from the infinitesimal dx, which is part of Calculus. dy/dx really means the limit of δt/δx as δx approaches zero. In Science, we are often too sloppy about these notations as there may be pitfalls when you don't stick to the 'rules' precisely.