Dynamical System (timtam's question at Yahoo Answers)

  • Context: MHB 
  • Thread starter Thread starter Fernando Revilla
  • Start date Start date
  • Tags Tags
    System
Click For Summary
SUMMARY

The discussion focuses on identifying a trapping neighborhood for the origin in the dynamical system defined by the equations xdot = -y - x√(x² + y²) and ydot = x - y√(x² + y²). It is established that the boundary defined by x² + y² = 1 indicates that the vector field points inward, confirming that the open unit disk serves as a trapping region. This conclusion is supported by the calculation showing that the dot product of the position vector and the velocity vector is negative, indicating stability within the region.

PREREQUISITES
  • Understanding of dynamical systems and their stability analysis
  • Familiarity with vector fields and their properties
  • Knowledge of mathematical concepts such as dot products and closed sets
  • Basic proficiency in calculus, particularly in dealing with polar coordinates
NEXT STEPS
  • Study the concept of trapping regions in dynamical systems
  • Learn about stability criteria in nonlinear systems
  • Explore vector field analysis techniques
  • Investigate the implications of closed sets in dynamical systems
USEFUL FOR

Mathematicians, physicists, and students studying dynamical systems, particularly those interested in stability analysis and vector field behavior.

Fernando Revilla
Gold Member
MHB
Messages
631
Reaction score
0
Here is the question:

For the system:
xdot= -y -xsqrt(x^2+y^2)
ydot= x -ysqrt(x^2+y^2)
Find a trapping neighbourhood for the origin.

Here is a link to the question:

Trapping neighbourhood (dynamical systems)? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
Physics news on Phys.org
Hello timtam,

On $x^2+y^2=1$ we have $$(x,y)\cdot v(x,y)=(x,y)\cdot \left(-y -x\sqrt{x^2+y^2},x -y\sqrt{x^2+y^2}\right)=\ldots=-2<0$$ That is, on the boundary of the closed set $R\equiv x^2+y^2\le 1$ the vector field is pointing towards the interior of $R$ so, the open unit disk is a trapping region.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K