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**Dynamics -- supertanker coasting to a stop**

1. Problem

Assuming constant negative acceleration, how far does a supertanker of a mass of 250000 metric tons travel while coasting to a stop from an initial speed of 30 km/h in 21 min?

What force is supplied by fluid friction of the water while the tanker is stopping?

2. Relevant formulas

S-S0 = (V+V0)t/2

ma = sum (F)

(1/2)at^2+v0t+S0=0

v=at+v0

3. Work I Did

250k met ton = 250,000,000 kg

30 km/h = 500 m/s

21 min = 1260 s

0 = 1260a + 500

a = -500/1260

(0+500)/2*1260 = 315 km (part a)

ma = -F(friction)

1000*(-50/126); Ff = 396.82 N (part b)

a: 5.25 km

b: 1.65*10^6 N