E field induced by changing B field

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SUMMARY

The discussion centers on calculating the electric field strength induced by a changing magnetic field inside a solenoid. Given a magnetic field of 2.0 T decreasing at a rate of 4.90 T/s in a solenoid with a diameter of 5.0 cm, the initial calculation for the electric field strength was determined to be 0.06125 V/m. However, it was concluded that the electric field strength should actually be 0 V/m due to the distance from the axis being 0, which indicates no induced electric field at that specific point.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with solenoid characteristics and magnetic fields
  • Knowledge of the relationship between changing magnetic fields and induced electric fields
  • Proficiency in using the formula E=(r/2)*(dB/dt)
NEXT STEPS
  • Study Faraday's Law of Electromagnetic Induction
  • Explore the concept of magnetic flux and its relation to electric fields
  • Investigate the behavior of electric fields in solenoids
  • Learn about the implications of distance from the axis in solenoid calculations
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in the principles of electric and magnetic field interactions.

Zywo
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Homework Statement


The magnetic field inside a 5.0-cm-diameter solenoid is 2.0 T and decreasing at 4.90 T/s
What is the electric field strength inside the solenoid at point on the axis?

Homework Equations


E=(r/2)*(dB/dt)

The Attempt at a Solution



E=(.025/2)*(4.9)= 0.06125 V/m

Not sure what's wrong here...

Thanks,
David
 
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Should be 0 because the distance from the axis is 0.
 
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