E- p+ collision product energies

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SUMMARY

In an electron-proton collision (p + e− → n + νe), the energy distribution between the neutron and the neutrino is influenced by the collision dynamics. Higher energy protons or electrons, such as those at 3 GeV, result in neutrinos with energies in the GeV range. In the center of mass frame, the neutron and neutrino carry opposite momentum, but their energy comparison varies based on their mass. The lab frame can complicate this distribution, leading to a broader range of energies for the collision products.

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  • Understanding of particle physics concepts, specifically electron-proton interactions.
  • Familiarity with energy-momentum conservation in particle collisions.
  • Knowledge of the center of mass frame versus lab frame in collision analysis.
  • Basic principles of neutrino physics and their role in particle decay processes.
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Physicists, particle accelerator researchers, and students studying high-energy particle interactions will benefit from this discussion.

Zypheros_Knight
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Greetings! This is probably the most simplest of questions but I wanted to ask that which particle carries most of the energy of an electron-proton collision (as in p + e−n + νe), the neutron or the neutrino? What happens if we use a higher energy proton or electron? For example we use electrons of sufficient energy (ie. 3GeV), will the resulting collision products contain higher energy neutrinos(with energies in GeV range) or not?

Edit: I'm only interested in an event in which a neutrino is emitted not in delta baryon resonances, bremsstrahlung radiation, pair production etc.
 
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In the center of mass frame they have to carry opposite momentum. At the same momentum, how does the energy of lighter and heavier particles compare?

In the lab frame things can be different in general, and you will get a broad distribution of energies for both products if your lab frame is not the center of mass frame.
 

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