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Each Car has Speed Corresponding to Max Normal Acceleration. Find Time Elasped

  1. Feb 3, 2013 #1
    1. The problem statement, all variables and given/known data
    The two cars A and B enter an unbanked and level turn. They cross line C-C simultaneously, and each car has the speed corresponding to a maximum normal acceleration of 0.94g in the turn. Determine the elapsed time for each car between its two crossings of line C-C. What is the relative position of the two cars as the second car exits the turn? Assume no speed changes throughout.

    I have attached an image of the question.

    2. Relevant equations

    an = v2/ρ = rθ'2 = vθ'

    v = rθ'



    3. The attempt at a solution

    I' honestly not sure how to start this one. I know an = 0.94g = 9.2214 m/s2

    I was thinking of something along the lines:

    v = rθ' = r dθ/dt

    ∫v dt = ∫r dθ

    vt = rθ

    t = rθ/v

    I'm not sure if what I have here makes sense. But if it does, could I substitute v for ds/dt, where ds/dt would be the circumference of the half circle?

    Honestly,I'm not sure if what I have makes sense. Any input/feedback would be greatly appreciated.
     

    Attached Files:

    Last edited: Feb 3, 2013
  2. jcsd
  3. Feb 3, 2013 #2
    Determine the speed of each vehicle from the formula V^2/r=a. Knowing the speed of each, determine the elapsed time for each vehicle to travel the distance realizing the distances differ. Then determine distance between vehicles.
     
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