Easy exponential question-> 1/3(8)^(-2/3)

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Homework Help Overview

The discussion revolves around simplifying the expression 1/3(8)^(-2/3) in the context of a linear approximation problem. Participants are exploring the mathematical properties of exponents and their application to this expression.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to clarify the interpretation of the expression, questioning whether it is meant as (1/3)(8^(-2/3)) or 1/(3(8^(-2/3))). There is also discussion about rewriting the expression using properties of exponents.

Discussion Status

The discussion is ongoing, with participants providing insights into the manipulation of the expression and exploring different interpretations. Some have suggested using brackets for clarity, while others have pointed out the relationship between the exponent and the base.

Contextual Notes

There appears to be some confusion regarding the notation and the intended operation, which may impact the simplification process. Participants are working within the constraints of a linear approximation context.

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Easy exponential question---> 1/3(8)^(-2/3)

Homework Statement



I am doing a linear approximation question, and got stuck here with this simple stuff.

1/3(8)^(-2/3)

Can anyone explain what I need to do to turn the above into 1/12 ?



Homework Equations





The Attempt at a Solution

 
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nukeman said:

Homework Statement



I am doing a linear approximation question, and got stuck here with this simple stuff.

1/3(8)^(-2/3)

Can anyone explain what I need to do to turn the above into 1/12 ?



Homework Equations





The Attempt at a Solution


$$8^{\frac{-2}{3}} = \frac{1}{8^{\frac{2}{3}}}$$
 


nukeman said:

Homework Statement



I am doing a linear approximation question, and got stuck here with this simple stuff.

1/3(8)^(-2/3)

Can anyone explain what I need to do to turn the above into 1/12 ?



Homework Equations





The Attempt at a Solution


What you have written reads as
\frac{1}{3} 8^{-2/3}. Is that what you meant, or did you want
\frac{1}{3\, 8^{-2/3}}?
If you mean the first one you should use brackets, like this: (1/3) 8^(-2/3), but if you mean the second one you should write 1/(8 2^(-2/3)).

RGV
 


As BloodyFrozen said, 8-2/3= 1/82/3. Further, since 23= 8, 81/3= 2 and so 82/3= 22= 4.
 

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