Undergrad EDE - Solving the Klein - Gordon Equation for a scalar field

Arman777
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Let us suppose we have a scalar field ##\phi##. The Klein-Gordon equations for the field can be written as

\begin{equation}
\ddot{\phi} + 3H \dot{\phi} + \frac{dV(\phi)}{d\phi} = 0
\end{equation}

The other two are the Friedmann equations written in terms of the ##\phi##

\begin{equation}
H^2 = \frac{8 \pi G}{3} [\frac{1}{2}\dot{\phi}^2 + V(\phi)]
\end{equation}

\begin{equation}
\dot{H} = -4 \pi G \dot{\phi}^2
\end{equation}

Now I need to solve these equations for the two cases.
1) Slow-roll approximation
2) Oscillation part.

In (1) we assume that
\begin{equation}
\dot{\phi}^2/2 \ll V_n(\phi)
\end{equation}

thus

$$|\ddot{\phi}| \ll |\frac{dV(\phi)}{d\phi}|$$

Under these conditions, equation (1) and (2) becomes\begin{equation}
3H \dot{\phi} + \frac{dV(\phi)}{d\phi} = 0
\end{equation}\begin{equation}
H^2 = \frac{8 \pi G}{3} V(\phi)
\end{equation}

The problem is that I cannot solve this equation. There is always one extra parameter. Can we define some sort of a general solution for this type of equation or do I need to provide some potential ?

I am trying to work on the Early Dark Energy (EDE) model. In the EDE model, similar to the inflation, we have two phases initially the field must have some initial value ##\phi_i## where the potential is constant. And then the field makes damped oscillations due to some reasons about the Hubble tension.

Do I need slow-roll parameters in order to solve it ?
 
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Maybe that helps:
-divide (5) by (6)
-make the approximation V'=V/phi
That gives phi as a function of H and t.
 
I always thought it was odd that we know dark energy expands our universe, and that we know it has been increasing over time, yet no one ever expressed a "true" size of the universe (not "observable" universe, the ENTIRE universe) by just reversing the process of expansion based on our understanding of its rate through history, to the point where everything would've been in an extremely small region. The more I've looked into it recently, I've come to find that it is due to that "inflation"...

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