Effect of Shielding on Electron Penetration

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SUMMARY

The discussion centers on the shielding effect in many-electron atoms and its impact on electron penetration. It is established that the 's' shell penetrates more effectively than 'p' or 'd' shells due to lower shielding, despite having a higher angular quantum number (l). The effective nuclear charge experienced by 's' electrons is greater because they are less shielded by other electrons, allowing them to be closer to the nucleus. This contradicts the initial assumption that higher angular quantum numbers would result in greater penetration.

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garvit21794
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as i have understood, in a many electron atom the degeneracy is lost due to shielding effect. and from quantum mechanical model of one electron atom we can say that keeping principal quantum number(n) fixed, the radius at which radial probability function takes maximum value decreases with increasing angular quantum number(l). then why is it that the 's' shell in many electron atom penetrates more than a 'p' or a 'd' shell and it experiences greater effective nuclear charge.? according to me it should have been the other way around.
 
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garvit21794 said:
as i have understood, in a many electron atom the degeneracy is lost due to shielding effect. and from quantum mechanical model of one electron atom we can say that keeping principal quantum number(n) fixed, the radius at which radial probability function takes maximum value decreases with increasing angular quantum number(l). then why is it that the 's' shell in many electron atom penetrates more than a 'p' or a 'd' shell and it experiences greater effective nuclear charge.? according to me it should have been the other way around.

The p and d shells have experience greater screening than the s shells as they don't penetrate so far in. As you say they have a greater average radius.
http://m.wikihow.com/Determine-Screening-Constant-and-Effective-Nuclear-Charge
 

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