Efficient Steps for Closed Form Summation: A Detailed Guide | 1.7^k and 2k"

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SUMMARY

The discussion centers on the closed form summation for the expressions 2k and 1.7^k. The closed form for the sum of the first n natural numbers is established as [n(n+1)]/2, leading to the expression for 2k as 2*[n(n+1)]/2. For the geometric series 1.7^k, the result is derived as [1.7^(n+1) - 1]/[1.7 - 1]. The final combined expression is confirmed as [2*[n(n+1)]/2] + [1.7^(n+1) - 1]/[1.7 - 1], which the author verifies through testing with various n values.

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mohabitar
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So here are my steps, which for some reason I feel are very wrong:

Well in closed form would be [n(n+1)]/2 so 2k would be 2*[n(n+1)]/2
For 1.7^k, I used a different form, which I don't have the formula for in front of me, but the final result for that part is [1.7^(n+1) - 1] /[1.7 - 1]

So the final answer I got was [2*[n(n+1)]/2] + [1.7^(n+1) - 1] /[1.7 - 1]

This feels incorrect to me for some reason. Can anyone confirm this or maybe this is correct?
 
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You can check it yourself. Try a few sums for different values of n and see if the formula you derived gives the same answer. If it does, you can be reasonably sure you have the correct result.
 
Well duh I don't know why I didnt think of that. Turns out my answer is correct. Thanks!
 

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