Effusing gas onto the interior of an evacuated sphere

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SUMMARY

The discussion centers on the effusion of gas into an evacuated sphere through a small hole, specifically addressing the uniformity of particle coating upon collision. Participants reference the angular probability distribution and surface area calculations, highlighting the formula for the surface area of a ring on a sphere. Key issues identified include the omission of hypotenuse length in the surface area formula and the need to account for varying angles of incidence. The conclusion emphasizes that the initial assumption of uniform particle distribution is incorrect due to these factors.

PREREQUISITES
  • Understanding of gas effusion principles
  • Familiarity with angular probability distributions
  • Knowledge of surface area calculations for spherical geometries
  • Basic grasp of particle dynamics in vacuum conditions
NEXT STEPS
  • Study the derivation of the angular probability distribution in effusion scenarios
  • Explore the impact of varying angles on particle collision outcomes
  • Investigate the mathematical modeling of gas behavior in vacuum environments
  • Learn about the implications of particle distribution in condensed matter physics
USEFUL FOR

Students and educators in physics, particularly those focusing on thermodynamics and kinetic theory, as well as researchers studying gas dynamics in vacuum systems.

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Homework Statement


A gas effuses into a vacuum though a small hole of area A. Show that if the particles effused into an evacuated sphere and the particles condensed where they collided that there would be a uniform coating. (7.6 of Blundell and Blundell)

Homework Equations



Angular probability distribution. The probability a particle is traveling between \theta and \theta+d\theta to the normal of the small hole.
$$
cos\theta sin\theta d\theta
$$

Surface area of a ring defined on the surface of a sphere with radius of unity where the angles go from \theta to \theta+d\theta

$$
2\pi sin\theta d\theta
$$

The Attempt at a Solution



Surely it would just be amount of particles over area which is proportional to cos\theta. This is clearly not uniform
 
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There are a few things wrong with your 2π sin(θ)dθ formula.
First, you have no hypotenuse length in there, and it will not be constant.
Second, you are not considering the oblique and varying angle between the beam and the surface.
Third, different dθ wedges will contain different fractions of the beam.
 

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