Effusion Equation Help | Find Expressions for v1 and v2

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SUMMARY

The discussion centers on deriving expressions for the most probable speeds of gas atoms, denoted as v1 and v2, in the context of effusion through a small hole. The effusion equation indicates that molecular flux is proportional to pressure (p) divided by the square root of temperature (T). Participants express confusion regarding the application of these principles to find the required expressions for v1 and v2, highlighting the need for clarity in the problem statement and solution approach.

PREREQUISITES
  • Understanding of the effusion equation and its implications in gas dynamics.
  • Familiarity with Maxwellian distribution and its application to molecular speeds.
  • Knowledge of the relationship between pressure, temperature, and molecular flux.
  • Basic proficiency in algebra and calculus for deriving expressions.
NEXT STEPS
  • Study the derivation of the effusion equation in detail.
  • Learn about Maxwell-Boltzmann statistics and its relevance to molecular speeds.
  • Explore the concept of molecular flux and its dependence on pressure and temperature.
  • Practice solving problems related to gas effusion and molecular dynamics.
USEFUL FOR

Students studying thermodynamics, physicists interested in gas behavior, and educators looking to clarify concepts related to molecular effusion and speed distributions.

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Homework Statement



Maxwellian gas effuses through a small hole to form a beam. After a certain distance from the hole, the beam hits a screen. Let v1 be the most probable speed of atoms that during a fixed time interval, hit the screen. Let v2 be the most probable speed of atoms situated at any instant between the small hole and screen. Find expressions for v1 and v2


Homework Equations





The Attempt at a Solution



So this is all we've been given, which is a bit confusing.

So i know the effusion equation..so I know that molecular flux is proportional to p over root T, but i just don't see how to do this question?!
 
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anyone...?
 

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