- #1

iamsmooth

- 103

- 0

[tex]\lambda^3-2\lambda^2[/tex]

I have double checked different row expansions to make sure this answer is correct. So don't worry about how I came to get that equation.

I'm just not sure how to get roots from this. Would it be:

[tex]\lambda^2(\lambda-2)[/tex]

So that the roots are 0 and 2?

Basically I have trouble with cubic roots, I guess this is less of a question about eigenvalues than it is about cubic roots.

Thanks.