Einstein model of solids, energy in joules of one quantum

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SUMMARY

The discussion centers on calculating the energy of one quantum for an atomic oscillator in a block of lead using the Einstein model of solids. The interatomic spring stiffness is established at 20 N/m, derived from the stiffness of the chemical bond and the configuration of the oscillator. The mass of a single lead atom is calculated as 3.44e-25 kg, leading to the final energy calculation of 8.0427e-22 J for one quantum. The error in the initial calculation was identified as using the mass of one mole instead of one atom.

PREREQUISITES
  • Understanding of the Einstein model of solids
  • Familiarity with quantum mechanics concepts, specifically energy quantization
  • Knowledge of basic physics equations, particularly E= hbar*sqrt(k/m)
  • Ability to perform calculations involving Avogadro's number (6.02e23)
NEXT STEPS
  • Explore the implications of the Einstein model on heat capacity in solids
  • Learn about the derivation and applications of Planck's constant in quantum mechanics
  • Investigate the relationship between interatomic forces and thermal properties of materials
  • Study the concept of microstates and its relevance in statistical mechanics
USEFUL FOR

Students and professionals in physics, particularly those focusing on solid-state physics, quantum mechanics, and materials science, will benefit from this discussion.

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Homework Statement


the stiffness of the interatomic "spring" (chemical bond) between atoms in a block of lead is 5 N/m. Since in our model each atom is connected to two springs, each half the length of the interatomic bond, the effective "interatomic spring stiffness" for an oscillator is 4*5 N/m = 20 N/m. The mass of one mole of lead is 207 grams (0.207 kilograms).

What is the energy, in joules, of one quantum of energy for an atomic oscillator in a block of lead?


Homework Equations


E= hbar*sqrt(k/m)


The Attempt at a Solution


E=(1.05457148e-34)(sqrt(20/.207)
E=1.033e-33 J

After this i thought that i would just divide this number by the total number of oscillators and get the energy for one quanta, but that doesn't work. This is the only equation given in the book besides the one for finding the possible number of microstates, but i don't see how that would help.
 
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I think you're done. It asks for the quantum of energy for an (as in one) atomic oscillator, and that is what you did.
 
Oh I figured out why it was wrong, its supposed to be the mass of one atom, not one mole. so m = .207/6.02e23
E=hbar*sqrt(20/m)
E=8.0427e-22 J
 
Aaargh, I missed that. Good catch.
 

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