Either the question is wrong or I'm missing something obvious

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SUMMARY

The discussion centers on the derivation of the kinematic wave equation for traffic flow as presented in exercise 2.4.2 from Pringle and King, Astrophysical Flows (CUP 2007). The key conclusion is that the maximum traffic flow occurs at a critical density, denoted as ρcrit, which corresponds to a critical speed vcrit of approximately 75 kph. The relationship between local density ρ and velocity v is established through the flux function Q(ρ) = V0ρ log(ρmax/ρ), with V0 set at 25 kph and ρmax at 150 vehicles/km. The analysis highlights the importance of considering wave propagation in traffic flow dynamics.

PREREQUISITES
  • Understanding of kinematic wave equations
  • Familiarity with traffic flow theory
  • Knowledge of calculus, specifically derivatives
  • Basic concepts of fluid dynamics as applied to vehicular flow
NEXT STEPS
  • Study the derivation of the kinematic wave equation in traffic flow models
  • Explore the implications of wave propagation in high-density traffic scenarios
  • Investigate the relationship between traffic density and flow rates using real-world data
  • Learn about advanced traffic simulation tools that model vehicle interactions
USEFUL FOR

Traffic engineers, physicists studying fluid dynamics, and researchers in transportation systems will benefit from this discussion, particularly those interested in modeling and optimizing traffic flow dynamics.

pasmith
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Homework Statement



This is exercise 2.4.2 from Pringle and King, Astrophysical Flows (CUP 2007):

Along an infinite, straight, one-track road the local density of cars is \rho(x,t) and the local velocity of cars (all assumed to be traveling in the same direction) is v(x,t). Discuss why it might be reasonable to assume that v is solely a function of \rho.

Making this assumption, show that <br /> \frac{\partial \rho}{\partial t} + c(\rho) \frac{\partial \rho}{\partial x} = 0<br /> where the kinematic wave speed is defined by c(\rho) = Q&#039;(\rho) and Q = \rho v is the local flux of cars.

Traffic flow along a particular highway can be fitted approximately for \rho &lt; \rho_{\mathrm{max}} by Q(\rho) = V_0\rho \log(\rho_{\mathrm{max}}/\rho), where V_0 = 25\,\mathrm{kph} and \rho_{\mathrm{max}} = 150\,\mathrm{vechicles}\,\mathrm{km}^{-1}.

Show that information propagates upstream at a speed V_0 relative to the local vehicle velocity.

Show that there is a maximum traffic flow which occurs at some density \rho_{\mathrm{crit}} corresponding to a critical speed v_{\mathrm{crit}} of around 75 kph.

[Remainder omitted]

Homework Equations





The Attempt at a Solution



All is straightforward until we consider the particular choice of Q. Firstly we have <br /> c = Q&#039; = V_0\left(\log(\rho_{\mathrm{max}}/\rho) - 1\right) = \frac Q\rho - V_0 = v - V_0 so indeed c - v = -V_0.

Now we're asked to find the maximum traffic flow. This corresponds to the maximum of Q, and we've just shown that Q&#039; = v - V_0. Thus the maximum occurs at v_{\mathrm{crit}} = V_0, at which point \rho_{\mathrm{crit}} = e^{-1}\rho_{\mathrm{max}}.

According to the question, v_{\mathrm{crit}} \approx 3V_0. Am I missing something obvious, or is the question wrong?
 
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You apparently had no problem deriving the kinematic wave equation (you didn't ask for help on that part), but then you promptly ignored that "waviness" in the rest of your analysis. You need to account for the fact that traffic flows in waves, at least when density is high enough.

You found the maximum instantaneous flux. It's the traffic flux ##\bar Q## averaged over time that you should be maximizing rather than that instantaneous flux.
 

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