Elastic collision and kinetic energy problem?

Click For Summary

Homework Help Overview

The problem involves an elastic collision between a compact hard sphere and a thin, uniform bar on a frictionless surface. The sphere strikes the bar at a specific distance from its center, and the task is to find the ratio of their masses, m/M, given that the sphere comes to rest after the collision.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of kinetic energy and angular momentum in elastic collisions. There are attempts to relate the equations of motion and inertia to find the mass ratio. Questions arise about how to set up the equations correctly and whether to equate them directly.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to relate the conservation equations. Some guidance has been provided regarding the use of angular momentum and energy conservation, but there is no explicit consensus on the method to solve for the mass ratio.

Contextual Notes

Participants are working within the constraints of the problem statement, focusing on the elastic nature of the collision and the specific setup involving the bar's rotation about its center. There is an emphasis on deriving relationships rather than providing direct solutions.

LarryJ
Messages
5
Reaction score
0

Homework Statement


The figure below shows a thin, uniform bar whose length is L and mass is M and a compact hard sphere whose mass is m. The system is supported by a frictionless horizontal surface. The sphere moves to the right with velocity , and strikes the bar at a distance 1/4L from the center of the bar. The collision is elastic, and following the collision the sphere is at rest. The rod is being rotated from its center. Find the value of the ratio m/M.


Homework Equations


1/2mv^2=1/2Iω^2


The Attempt at a Solution


I know the collision is elastic, so kinetic energy is conserved. But I don't know exactly how find which mass ratios will make the collision elastic. I think I know inertia (1/12MR^2). But I'm basically stuck from there.
 
Physics news on Phys.org
Hi LarryJ! :smile:

(try using the X2 button just above the Reply box :wink:)
LarryJ said:
I know the collision is elastic, so kinetic energy is conserved. But I don't know exactly how find which mass ratios will make the collision elastic. I think I know inertia (1/12MR^2). But I'm basically stuck from there.

angular momentum is also conserved (in any collision, and about any point)

also, you are told that the bar rotates about its centre

so write out the equations for conservation of energy, and for conservation of angular momentum about the centre …

what do you get? :smile:
 
Kinetic energy: 1/2mv2=1/2Iω2
Angular Momentum: (1/12MR2)(ω)= mv(1/4R)2
So do I set the equations equal to each other and then solve for M and m?
 
LarryJ said:
So do I set the equations equal to each other and then solve for M and m?

i'm not sure what you mean by "set the equations equal to each other",

but yes, you solve for m/M :smile:
 
How do I set up an equation to solve for M and m?
 
try squaring one equation :smile:
 
Oh I think I got it. 0.57:approve:
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
10
Views
3K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 18 ·
Replies
18
Views
2K
Replies
21
Views
3K
  • · Replies 16 ·
Replies
16
Views
4K
Replies
20
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K