Elastic collision between 2 different masses

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In the discussion about elastic collisions between two different masses, participants emphasize the conservation of momentum as a vector quantity, requiring separate equations for the x and y components. The angle θ2 is derived from the relationship with θ1, where θ1 is calculated as tan⁻¹(2), leading to θ2 being 90° - θ1. However, it is clarified that the angles do not necessarily add up to 90° unless the masses are equal. The need for using both px and py equations is confirmed to solve the problem accurately. Understanding these principles is crucial for solving elastic collision problems effectively.
Yeldarb
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Homework Statement


See picture

Homework Equations


p = p1 +p2
p = mv

The Attempt at a Solution


See picture, using equations for the velocity and using 90-tan-1(2) for the angle
 

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Do not forget that momentum is a vector quantity. Both of its components are conserved.
Why do you think that θ2=90-tan-1(2)?
 
ehild said:
Do not forget that momentum is a vector quantity. Both of its components are conserved.
Why do you think that θ2=90-tan-1(2)?
Does this mean that I need to use a px and a py equation? Does what I got help me at all? The picture shows tan(theta1)=2, so theta1= tan-1(2) and since the angle between the two should be 90, 90-theta1 =theta2

Thanks
 
Yeldarb said:
Does this mean that I need to use a px and a py equation? Does what I got help me at all? The picture shows tan(theta1)=2, so theta1= tan-1(2) and since the angle between the two should be 90, 90-theta1 =theta2

Thanks
What makes you think the angle between their directions is 90° ?

q-png.91722.png
 
Yeldarb said:
Does this mean that I need to use a px and a py equation? Does what I got help me at all? The picture shows tan(theta1)=2, so theta1= tan-1(2) and since the angle between the two should be 90, 90-theta1 =theta2

Thanks
Yes, you need an equation for px and an other one for py. NO, the two angles do not add up to 90°. It happens if the two masses are equal.
 

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