Elastic Collision: Find V1', V2' with M1, M2, V1, V2

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In the discussion on elastic collisions, participants analyze a scenario involving two colliding objects with known masses and initial velocities. The equations for conservation of momentum and kinetic energy are used to derive final velocities, V1' and V2', resulting in V1' = -7 m/s and V2' = -1 m/s. A question arises about manipulating the equations to solve for initial conditions when some variables are unknown, specifically asking if it's feasible to determine mass M2 and initial velocity V1 with given final velocities. The consensus is that it is challenging to solve for three variables with only two equations, suggesting that additional information or constraints are necessary for a solution. The discussion highlights the complexity of algebraic manipulation in collision problems.
Ajwrighter
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1. Two objects collide M1 = 1kg M2 = 3kg V1 = 2m/s V2 = -4 m/s V1' = ? V2' =?



2. PEi = PEf m1v1 + m2v2 = m1V1' + m2v2' KEi=KEf same as (1/2)(PE^2)/m



3. PEi = PEf ----> 2 - 12 = -10 ---> v2' = (-10 - v1')/3
KEi = KEf ----> 4 + 48 = 52 ----> 156 3Vi^2' + V1^2' + 20v' +100


4. V1' = - 7 V2' = -1
KEi = 2J + 24J = 26J KEf = 24.5J + 1.5J = 26J




The real Question: I tried to manipulate the problem with algebra but to no ends. So here is my question, how do you obtain V1 or V2 with (not V1' or V2') Can you obtain your numbers if let's say you have

1. Two objects collide M1 = 1kg M2 = ? V1 = ? V2 = -4 m/s V1' = -7 V2' =? What format would you use to solve this. I tride using the same equations but I can't seem to manipulate the algebra to do what I want. I keep getting either really small or really large numbers.[/
 
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I don't understand, you have 3 variables and two equations? Also your equations are almost unreadable.
 
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I just zipped by to show that i can do it and have gotten the answer. Was wondering if there was a way to obtain an answer if the variables where miss matched . so instead of the equation asking for V1' and V2' (like stated above) it would be asking for M2, V1 and V2' =?
 
You can do it? Show me please!

I think it's impossible when you have only two equations for three variables. (Unless you can eliminate two variables at once somehow...)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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