A mass m1 moving with u collides with mas m2...

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Homework Help Overview

The problem involves a collision between two masses, m1 and m2, where m1 is initially moving with a velocity u and m2 is stationary. The goal is to determine the fraction of energy converted into heat and sound during the collision, and to show that this energy is equal to the kinetic energy from the center of mass reference frame.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the conservation of momentum and energy equations, questioning the relationship between kinetic energy and the energy converted into heat and sound. There are attempts to express the energy in terms of the velocities after the collision and to relate it to the center of mass reference frame.

Discussion Status

Some participants are exploring the implications of elasticity in the collision, noting that the results may vary if the system is elastic. There is a recognition of the need to eliminate certain variables to simplify the equations, and a few participants express uncertainty about their calculations and interpretations.

Contextual Notes

There is a lack of explicit information regarding the elasticity of the collision, which is noted as a potential factor affecting the outcome. Participants are also grappling with the implications of their assumptions about the masses sticking together post-collision.

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Homework Statement


A mass m1 collides with stationary m2 with velocity u1 u. Find the fraction of energy converted into heat and sound. Show that this energy is equal to the kinetic energy from centre of mass reference frame

Homework Equations


[/B]
let v1 and v2 be velocity of m1 and m2 after collision :

e = v2-v1/u1

m1u1 = m1v1 + m1v1

ke = 1/2 mv^2

The Attempt at a Solution



let k be energy by sound and heat.

m1(u1-v1) = m2v2 (1)

m1u1^2 - m1v1^2 = k + m2v2^2

= m1(u1+v1) (u1-v1)

dividing by 1

u1+v1 = k/m2v2 + v2

u1 = k/m2v2 + v2 - v1

1 = k/(m2v2u1) + e

(1-e)*m2v2u1 = k

annnd stuck. this is the farthest I've gotten and doesn't look like velocity from com reference frame at all : (going further the ratio with initial ke is

(1-e)*m2/m1*v2/u1 which ia nice and symmetric i guess. but i guess it wants me to do stuff and rid off v2 and end up with an ugly expression. I don't think that's right
 
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Vriska said:
Show that this energy is equal to the kinetic energy from centre of mass reference frame
Based on that, I presume you were told that the masses stick together?
Vriska said:
m1u1^2 - m1v1^2 = k + m2v2^2
Should be 2k?

What is the initial KE in the common mass centre reference frame?
 
haruspex said:
Based on that, I presume you were told that the masses stick together?

Should be 2k?

What is the initial KE in the common mass centre reference frame?

right it's 2k.

initial ke looks to be
: m1m2* u^2/2(m1+m2). The final will be u replaced by ku i guess.

no mention is given about the elasticity of the system : \
 
Vriska said:
no mention is given about the elasticity of the system : \
The result you are asked to prove will not be true if there is any elasticity. There will remain some KE.
 
haruspex said:
The result you are asked to prove will not be true if there is any elasticity. There will remain some KE.

damn i was trying this all day : (

but then shouldn't my answer have m1^2 instead of m1m2?

Anyway here's the question in case I'm misreading something
 

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Vriska said:
shouldn't my answer have m1^2 instead of m1m2?
It should not have v2. Use the equations you have to eliminate that and see what happens.
 

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