Elastic Collision: Kinetic Energy and Spring Compression

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Homework Help Overview

The discussion revolves around an elastic collision problem involving a boulder sliding down a hill and colliding with a spring. The context includes calculating kinetic energy and spring compression after the collision.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using conservation of energy to find the kinetic energy at the bottom of the incline and the work done by friction. There are attempts to clarify the equations and symbols used in the calculations.

Discussion Status

Some participants have provided guidance on using conservation of energy, while others have questioned the representation of quantities in the equations. Multiple interpretations of the problem setup are being explored.

Contextual Notes

There is mention of friction affecting the energy calculations, and the original poster expresses uncertainty about their understanding and attempts to engage peers for assistance.

geauxKTM
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Elastic collision, I think?

Homework Statement

50kg boulder slides down a 5m high, 20m long hill against friction force 40N. At the top the boulder is moving at 2m/s. At the base of hill the boulder slides on a horizontal frictionless surface for a short distance and then collides with a tree having spring constant 5000N/m. A. Find the kinetic energy at the bottom of the incline. B. find distance the spring(tree) is compressed or bent when the boulder stops



Homework Equations

Ff=40N m=50 V0=2 I am lost. For B f=kx right?



The Attempt at a Solution

No attempt and I have 3 of the smarter students sitting with me so please help. I seem to always receive feedback too late and I realize this is a weak attempt but I do have at least 4 more to post with a better understanding
 
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Use conservation of energy. What is the total energy at the top? What is the work done by friction? When you get these two, you can get the kinetic energy at the bottom.
 


rock.freak667 said:
Use conservation of energy. What is the total energy at the top? What is the work done by friction? When you get these two, you can get the kinetic energy at the bottom.

Thank you very much, is this right?. A.Ui+W=Kf (50(9.8)5)+(40*20)=3250J
B. 3250=500x^2
 


Your equation should be mgh=1/2 mv2+Ffrictiond. Not sure which quantities were represented by your symbols.
 

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