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## Homework Statement

A pinball with mass 80g is struck by a lever with mass 80g in a pinball machine in an elastic collision. The lever was pulled back 2 cm by a spring with spring constant k=1.4N/cm. What is the speed of the ball just after collision?

## Homework Equations

F=kx

1/2kx^2=1/2mv^2

M1V1 = M2V2

## The Attempt at a Solution

1/2 (2.8)(4)=5.6 5.6=1/2 (80) v^2 <-- trying to find velocity of lever just before contact

5.6/40 = v^2 V=.37

now this is where i get even more stuck, the masses of the ball and the lever are equal and they cancel out in the equation M1V1 = M2V2, which would leave the velocities as being equal. However, the answer choices are as follows:

A) 1.1 m/s

B) 1.4 m/s

C) 11 m/s

D) 14 m/s

If someone can shed some light on how to solve this problem it would be greatly appreciated.