Electric Field and Potential Change in a System with Equipotential Surfaces

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Homework Help Overview

The problem involves analyzing a system with equipotential surfaces, specifically focusing on determining the electric field's magnitude and direction, as well as calculating the shortest distance to achieve a specified change in potential. The context is rooted in electrostatics and the relationship between electric fields and potential differences.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the equations relevant to electric fields and potential differences, with one participant suggesting the use of delta V = -W/qo. There is a focus on understanding the relationship between electric field strength (E), potential (V), and distance (r). Questions arise about the correct interpretation of distances between equipotential surfaces and the angles involved in the geometry of the problem.

Discussion Status

The discussion has progressed with participants exploring different interpretations of the geometry involved. Some have provided guidance on how to approach the problem, particularly regarding the need to consider distances perpendicular to equipotential lines. There is an acknowledgment of mistakes made in calculations and units, leading to corrections and further exploration of the problem.

Contextual Notes

Participants note the importance of unit conversions, specifically from centimeters to meters, which affects the calculations of the electric field. There is also a mention of the need to clarify the number of significant figures required for the answers.

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Problem:

A given system has the equipotential surfaces shown below, where Vo = 12.0 V.

20-26alt.gif


(a) What are the magnitude and direction of the electric field?
(b) What is the shortest distance one can move to undergo a change in potential of 5.00 V?

I am not too sure on what equations I can use to solve this, but I have a feeling one of them will be delta V = -W/qo, and I have no other ideas on how to approach this problem.
 
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You need trig to figure out the distance between the equipotentials. The electric field is always going to be orthogonal to equipotential surfaces. Do you know the relationship between E, V and r? Use that to find E, then use the E that you got from part a) for the last part.
 
Okay, so for part (a), I use E = - V/r = - 12/4 = -3? Did I interpret your post correctly?
 
Not quite, you need the distance between two equipotential lines, which would be along a line perpendicular to them. I think you've gone along the x axis, which is at an angle to the red lines. Use the triangle formed by the x and y axes and the line V=V0, split it into two smaller right angled triangles and look for similar angles.
 
Okay, I determined how to split the triangle into two smaller right triangles and found the smiliar angles, but what exactly is this telling me?
 
You should be able to get the distance between the equipotentials, which is your r in E=-V/r. Also, one of the angles gives you the direction of the E field.
 
Oh, okay, so the distance between the lines is 1.78885 m, so this is my r. So plugging this into E = -V/r = -12/1.78885 = -6.7082 V/m?

Edit: I just tried submitting this answer (both negative and positive), and both were incorrect.
 
Last edited:
That's odd, that's the answer I got. Have you added the direction? Does it say how many s.f. to give?
 
I found my mistake. The units in the chart are in cm, so I converted all values into m. This gave me a value of 670.82, which is a correct answer. I also calculated the correct answer for the direction, which is 243 degrees counterclockwise from the +x axis. I also solved part (b). Thank you for your help!
 
Last edited:

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