Electric Potential- quick question about process

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Homework Help Overview

The discussion revolves around the concept of electric potential in the context of an alpha particle colliding with a lead nucleus. The original poster presents a problem involving kinetic energy and seeks clarification on a specific calculation related to energy conversion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions the reasoning behind converting kinetic energy from MeV to joules by multiplying by a specific factor (1.6e-19), indicating a need for understanding the relationship between energy units.

Discussion Status

Participants are engaged in clarifying the conversion of energy units and the implications for the problem. Some express gratitude for assistance, suggesting that helpful guidance has been provided, although no consensus has been reached on the broader aspects of the problem.

Contextual Notes

The problem assumes the lead nucleus remains stationary and treats it as a point charge, which may influence the interpretation of the electric potential involved in the collision scenario.

SuperCass
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Electric Potential-- quick question about process

Homework Statement



An alpha particle with kinetic energy 10 MeV makes a head-on collision with a lead nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.)

Homework Equations



V=kq/r

The Attempt at a Solution



http://www.solvephysics.com/electricity_problem26.shtml
I tried going by this site to solve this. I would just like to know why in the Einitial equation they multiply the 10MeV by 1.6e-19. Why do they do that? I don't understand.

Thanks!
 
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SuperCass said:

Homework Statement



An alpha particle with kinetic energy 10 MeV makes a head-on collision with a lead nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.)

Homework Equations



V=kq/r

The Attempt at a Solution



http://www.solvephysics.com/electricity_problem26.shtml
I tried going by this site to solve this. I would just like to know why in the Einitial equation they multiply the 10MeV by 1.6e-19. Why do they do that? I don't understand.

Thanks!


http://en.wikipedia.org/wiki/Electronvolt
 


Thank you so much, I would have never gotten that on my own!
 


SuperCass said:
Thank you so much, I would have never gotten that on my own!

It should be in your textbook as well.
 

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