Electric Potential: Find x for Zero Net Electric Potential

Click For Summary
SUMMARY

The discussion focuses on determining the positions along the x-axis where the net electric potential is zero for two fixed charges: q1=+5e and q2=-15e, separated by 0.24m. The key conclusion is that valid solutions for x exist only within the range 0 PREREQUISITES

  • Understanding of electric potential and electric fields
  • Familiarity with Coulomb's law and the concept of charge
  • Knowledge of the formula for electric potential, V=Kq/r
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the concept of electric potential in more detail
  • Learn about the superposition principle in electrostatics
  • Explore the relationship between electric fields and potentials
  • Investigate the effects of varying charge magnitudes on electric potential
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone studying electrostatics, particularly those interested in understanding electric potential and its implications in charge interactions.

Air
Messages
202
Reaction score
0

Homework Statement


Particles of the charges q1=+5e (at origin) and q2=-15e are fixed in place with a separation of d=0.24m. With V=0 at infinity, what are the finite (a) positive and (b) negative values of x at which the net electric potential on the x-axis is zero?


Homework Equations


E=Kq/r


3. The problem I encounter
I can get the answer but I don't understand the position considered. Where do I consider my x value to be? Why don't we consider x to be greater than d? Why do we only consider for 0<x<d or x<d?
 
Physics news on Phys.org
x is the point where the electric fields from the charges cancel each other out. There are only two such points. You can consider x>d if you like but you won't find a point where the fields cancel each other because the field of q2 is always stronger in that region.
 
But we are considering potential. Do we understand through electric field then use the equation of potential?
 
Well, the only difference in the formula for the field is the power of r so qualitatively it's the same. In the region x>d the magnitude of q2 potential is always greater than that of q1. I just thought fields are more intuitive and illustrate better why there are only two points.
 

Similar threads

Replies
19
Views
3K
Replies
5
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K