Electrical Power - Equation Questions:

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Homework Help Overview

The discussion revolves around calculating energy storage and usage in a rechargeable cell and its application in lighting a bulb. The subject area includes electrical power, energy calculations, and circuit analysis.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore energy calculations in mWh and Joules, question the characteristics of the bulb, and discuss how long the cells can power the bulb based on current requirements.

Discussion Status

Some participants have provided calculations for energy storage and have begun to analyze the bulb's requirements. There is a recognition of the relationship between the cells' output and the bulb's consumption, with some confirming the calculations align with textbook answers.

Contextual Notes

Participants note the importance of the bulb's characteristics, including its voltage and current requirements, in determining how long the cells can power it. There is an acknowledgment of potential discrepancies in textbook answers.

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A 1.5V rechargeable cell is labelled 2300 mA h. This means that it can supply the equivalent of 2300 mA for one hour.

b) How much energy does the cell store in:
i- mWh?
ii- J?

and c) How long can four cells, connected in series, light the bulb?

for b) i- I got: W = V x Q, so W = V x I x t

W = 1.5V x 2.3A x 1second
= 3.45W = 3450mWh​

b) ii-
W = Js-1
J = W x t
J = 3.45 x 60 x 60
J = 12420 = 12.42kJ​


I know that I got b (i) and (ii) correct, expect I'm stuck on c). The previous sub-questions are just supplied to give more information :) Thanks
 
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What are the characteristics of the bulb (its wattage or current requirement)?
 
gneill said:
What are the characteristics of the bulb (its wattage or current requirement)?

Ah yeah, missed out some info. The bulb is labelled 6.0 V and 120mA... no wattage, but you could work that out, so P = 6V x 0.12W = 0.72W
 
You know that each cell will be depleted after one hour supplying 2300 mA. The bulb requires 120 mA. How long will they last at that rate?
 
Each cell will last... 2300mA shared by 120 mA ... so, 19.2 hours. And that's the right answer in the back of the book... wow. Hmm. Thanks! That is right isn't it? The textbook isn't always necessarily correct.
 
Yup. That's right.
 
Ah thanks again gneill!
 

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